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aayushi.somani
 2 years ago
Integrate :
(x1) root(1xx^2)
aayushi.somani
 2 years ago
Integrate : (x1) root(1xx^2)

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myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0Have you tried completing the square inside the square root first?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0This might end up being a trig sub.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0i will be back if you have questions

aayushi.somani
 2 years ago
Best ResponseYou've already chosen the best response.1yeah i tried it.. but that didnt worked !

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0u can take (x1) as u and the rest term as v and integrate by parts

aayushi.somani
 2 years ago
Best ResponseYou've already chosen the best response.1@ikram002p please help !

ikram002p
 2 years ago
Best ResponseYou've already chosen the best response.1addy :o is it like this ? \(\int (x1) \sqrt (1xx^2)\)

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0The trig sub seems to work Not saying there aren't other ways though

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0@aayushi.somani may I ask how far you got with that method?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0to what integral have you transformed it?

aayushi.somani
 2 years ago
Best ResponseYou've already chosen the best response.1i could not figure out anything

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0can you tell me what substitutions you performed ?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0some people like to do two here i just like one

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0When you say you could not figure out anything does that mean you did not do anything with the trig sub even though you said you did?

aayushi.somani
 2 years ago
Best ResponseYou've already chosen the best response.1i tried getting a trig sub but unfortunatly i couldnt.. thats what it is.. @ikram002p could u figure out?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0did you complete the square inside the square root part?

aayushi.somani
 2 years ago
Best ResponseYou've already chosen the best response.1if i could have done it then y would i ask this ques..??? @myininaya i asked so that anyone could help me..

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0Oh I'm sorry I didn't know you couldn't do the algebra either

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0So by nothing means absolutely nothing I get it

aayushi.somani
 2 years ago
Best ResponseYou've already chosen the best response.1from what i did m getting a wrong answer so consider i did nothing and now please help me from the very begnning..

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0\[ax^2+bx+c=a(x^2+\frac{b}{a}x)+c=a(x^2+\frac{b}{a}x+(\frac{b}{a})^2)+ca(\frac{b}{a})^2 \\ =a(x+\frac{b}{a})^2+ca \frac{b^2}{a^2}=a(x+\frac{b}{a})^2+c\frac{b^2}{a}\] I hope this helps you complete the square Please follow these steps I prefer you ask me questions on how to do this than just using the end result there

ikram002p
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1408601698600:dw i dont know if this work next to use tring mmm sin maybe ?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0oh mine what is all of that?

aayushi.somani
 2 years ago
Best ResponseYou've already chosen the best response.1u mean i gotto Rationalise? @ikram002p

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0You don't have to rationalize...And tht wouldn't be the way to rationalize the top anyhow

ikram002p
 2 years ago
Best ResponseYou've already chosen the best response.1:P ok we dont need conjucate xD just hmm 1x^2=(5/2(x+1/2)^2 >.<

aayushi.somani
 2 years ago
Best ResponseYou've already chosen the best response.1got it lol sorry :P

aayushi.somani
 2 years ago
Best ResponseYou've already chosen the best response.1i got the answer.. anyways thanks (:

ikram002p
 2 years ago
Best ResponseYou've already chosen the best response.1:o how did u get it ?

aayushi.somani
 2 years ago
Best ResponseYou've already chosen the best response.1I just made a small mistake.. I rechecked it.. and i could figure out the mistake! thankyou so much.. @ikram002p

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0I thought you didn't do any of it...

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0I want to go back to my completing square thingy... (i made some mistakes) \[ax^2+bx+c=a(x^2+\frac{b}{a}x)+c=a(x^2+\frac{b}{a}x+(\frac{b}{2a})^2)+ca(\frac{b}{2a})^2 \\ =a(x+\frac{b}{2a})^2+ca \frac{b^2}{4a^2}=a(x+\frac{b}{2a})^2+c\frac{b^2}{4a} \]
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