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myininaya Group TitleBest ResponseYou've already chosen the best response.0
Have you tried completing the square inside the square root first?
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
This might end up being a trig sub.
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
i will be back if you have questions
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
yeah i tried it.. but that didnt worked !
 3 months ago

vaibhavthacker95 Group TitleBest ResponseYou've already chosen the best response.0
u can take (x1) as u and the rest term as v and integrate by parts
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
@ikram002p please help !
 3 months ago

ikram002p Group TitleBest ResponseYou've already chosen the best response.1
addy :o is it like this ? \(\int (x1) \sqrt (1xx^2)\)
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
yeah exactly!
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
The trig sub seems to work Not saying there aren't other ways though
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
@aayushi.somani may I ask how far you got with that method?
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
to what integral have you transformed it?
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
i could not figure out anything
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
can you tell me what substitutions you performed ?
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
some people like to do two here i just like one
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
When you say you could not figure out anything does that mean you did not do anything with the trig sub even though you said you did?
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
I'm confused
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
i tried getting a trig sub but unfortunatly i couldnt.. thats what it is.. @ikram002p could u figure out?
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
did you complete the square inside the square root part?
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
if i could have done it then y would i ask this ques..??? @myininaya i asked so that anyone could help me..
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
Oh I'm sorry I didn't know you couldn't do the algebra either
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
So by nothing means absolutely nothing I get it
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
from what i did m getting a wrong answer so consider i did nothing and now please help me from the very begnning..
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
\[ax^2+bx+c=a(x^2+\frac{b}{a}x)+c=a(x^2+\frac{b}{a}x+(\frac{b}{a})^2)+ca(\frac{b}{a})^2 \\ =a(x+\frac{b}{a})^2+ca \frac{b^2}{a^2}=a(x+\frac{b}{a})^2+c\frac{b^2}{a}\] I hope this helps you complete the square Please follow these steps I prefer you ask me questions on how to do this than just using the end result there
 3 months ago

ikram002p Group TitleBest ResponseYou've already chosen the best response.1
dw:1408601698600:dw i dont know if this work next to use tring mmm sin maybe ?
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
oh mine what is all of that?
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
u mean i gotto Rationalise? @ikram002p
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
You don't have to rationalize...And tht wouldn't be the way to rationalize the top anyhow
 3 months ago

ikram002p Group TitleBest ResponseYou've already chosen the best response.1
:P ok we dont need conjucate xD just hmm 1x^2=(5/2(x+1/2)^2 >.<
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
got it lol sorry :P
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
i got the answer.. anyways thanks (:
 3 months ago

ikram002p Group TitleBest ResponseYou've already chosen the best response.1
:o how did u get it ?
 3 months ago

aayushi.somani Group TitleBest ResponseYou've already chosen the best response.1
I just made a small mistake.. I rechecked it.. and i could figure out the mistake! thankyou so much.. @ikram002p
 3 months ago

ikram002p Group TitleBest ResponseYou've already chosen the best response.1
:* np girl
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
I thought you didn't do any of it...
 3 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
I want to go back to my completing square thingy... (i made some mistakes) \[ax^2+bx+c=a(x^2+\frac{b}{a}x)+c=a(x^2+\frac{b}{a}x+(\frac{b}{2a})^2)+ca(\frac{b}{2a})^2 \\ =a(x+\frac{b}{2a})^2+ca \frac{b^2}{4a^2}=a(x+\frac{b}{2a})^2+c\frac{b^2}{4a} \]
 3 months ago
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