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aayushi.somani
 8 months ago
Integrate :
(x1) root(1xx^2)
aayushi.somani
 8 months ago
Integrate : (x1) root(1xx^2)

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myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0Have you tried completing the square inside the square root first?

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0This might end up being a trig sub.

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0i will be back if you have questions

aayushi.somani
 8 months ago
Best ResponseYou've already chosen the best response.1yeah i tried it.. but that didnt worked !

vaibhavthacker95
 8 months ago
Best ResponseYou've already chosen the best response.0u can take (x1) as u and the rest term as v and integrate by parts

aayushi.somani
 8 months ago
Best ResponseYou've already chosen the best response.1@ikram002p please help !

ikram002p
 8 months ago
Best ResponseYou've already chosen the best response.1addy :o is it like this ? \(\int (x1) \sqrt (1xx^2)\)

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0The trig sub seems to work Not saying there aren't other ways though

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0@aayushi.somani may I ask how far you got with that method?

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0to what integral have you transformed it?

aayushi.somani
 8 months ago
Best ResponseYou've already chosen the best response.1i could not figure out anything

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0can you tell me what substitutions you performed ?

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0some people like to do two here i just like one

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0When you say you could not figure out anything does that mean you did not do anything with the trig sub even though you said you did?

aayushi.somani
 8 months ago
Best ResponseYou've already chosen the best response.1i tried getting a trig sub but unfortunatly i couldnt.. thats what it is.. @ikram002p could u figure out?

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0did you complete the square inside the square root part?

aayushi.somani
 8 months ago
Best ResponseYou've already chosen the best response.1if i could have done it then y would i ask this ques..??? @myininaya i asked so that anyone could help me..

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0Oh I'm sorry I didn't know you couldn't do the algebra either

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0So by nothing means absolutely nothing I get it

aayushi.somani
 8 months ago
Best ResponseYou've already chosen the best response.1from what i did m getting a wrong answer so consider i did nothing and now please help me from the very begnning..

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0\[ax^2+bx+c=a(x^2+\frac{b}{a}x)+c=a(x^2+\frac{b}{a}x+(\frac{b}{a})^2)+ca(\frac{b}{a})^2 \\ =a(x+\frac{b}{a})^2+ca \frac{b^2}{a^2}=a(x+\frac{b}{a})^2+c\frac{b^2}{a}\] I hope this helps you complete the square Please follow these steps I prefer you ask me questions on how to do this than just using the end result there

ikram002p
 8 months ago
Best ResponseYou've already chosen the best response.1dw:1408601698600:dw i dont know if this work next to use tring mmm sin maybe ?

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0oh mine what is all of that?

aayushi.somani
 8 months ago
Best ResponseYou've already chosen the best response.1u mean i gotto Rationalise? @ikram002p

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0You don't have to rationalize...And tht wouldn't be the way to rationalize the top anyhow

ikram002p
 8 months ago
Best ResponseYou've already chosen the best response.1:P ok we dont need conjucate xD just hmm 1x^2=(5/2(x+1/2)^2 >.<

aayushi.somani
 8 months ago
Best ResponseYou've already chosen the best response.1got it lol sorry :P

aayushi.somani
 8 months ago
Best ResponseYou've already chosen the best response.1i got the answer.. anyways thanks (:

ikram002p
 8 months ago
Best ResponseYou've already chosen the best response.1:o how did u get it ?

aayushi.somani
 8 months ago
Best ResponseYou've already chosen the best response.1I just made a small mistake.. I rechecked it.. and i could figure out the mistake! thankyou so much.. @ikram002p

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0I thought you didn't do any of it...

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.0I want to go back to my completing square thingy... (i made some mistakes) \[ax^2+bx+c=a(x^2+\frac{b}{a}x)+c=a(x^2+\frac{b}{a}x+(\frac{b}{2a})^2)+ca(\frac{b}{2a})^2 \\ =a(x+\frac{b}{2a})^2+ca \frac{b^2}{4a^2}=a(x+\frac{b}{2a})^2+c\frac{b^2}{4a} \]
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