anonymous
  • anonymous
In a hospital ward, there are 12 nurses and 4 doctors. 3 of the nurses and 2 of the doctors are male. If a person is randomly selected from this group, what is the probability that the person is female or a doctor? @IMStuck @TheSaint905621 @Compassionate @phi @math&ing001 @acxbox22
Statistics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@TSwizzle @TheSaint905621
anonymous
  • anonymous
11/16
anonymous
  • anonymous
\[P(\text{female or doctor})=P(\text{female})+P(\text{doctor})-P(\text{female and doctor})\] There's a total of 11 females (9 nurses, 2 doctors) in the group of 16, and there are 4 doctors. Two of these doctors are also female, so \[P(\text{female or doctor})=\frac{11}{16}+\frac{4}{16}-\frac{2}{16}\]

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