Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

JeSuisDavid Group Title

A projectile is launched from ground level at an angle of 35 degrees above the horizontal line (x-axis??) with an initial velocity of 65m/s. Determine the time when |v|=58m/s

  • one month ago
  • one month ago

  • This Question is Closed
  1. ProfBrainstorm Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Here's one way you could solve it - Firstly you need to consider the horizontal and vertical components of the velocity separately. The horizontal motion has no acceleration. The vertical motion has the acceleration due to gravity, g. Write down expressions for each component of the velocity as a function of time. Then you can use the expression \[v^2=v _{x}^2+v _{y}^2\] to get an equation relating v and t. You should end up with a quadratic equation for t.

    • one month ago
  2. Mashy Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    and bonus question when u solve the quadratic equation.. you ll get two answers (both positive) ... can u think WHY you get two answers?? and bonus question 2 for one particular value of |v|.. the quadratic equation will be a perfect square and yield one answer only. Again can u think.. why would it be that? (also can u find what that |v| is and what that time is?) ;-)

    • one month ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.