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anonymous

  • one year ago

Dosha is creating a new dessert that has two layers shaped like cones. The inner cone is frozen ice cream and has a diameter of 12 cm and a height of 6 cm. The outer layer is a thin wafer shell, like an upside-down ice cream cone, with a height of 15 cm and the same diameter as the inner layer. Dosha will inject a cream filling into the space. What is the volume of the cream filling? Use 3.14 to approximate pi and express your final answer in hundredths.

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  1. anonymous
    • one year ago
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    \[Volume of cone = \frac{ 1 }{ 3 }\pi*r^2h\]

  2. anonymous
    • one year ago
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    Cone 1: Radius :6 cm Height :6 cm Cone 2 Radius :6 cm Height : 15cm

  3. anonymous
    • one year ago
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    cone 1= 226.08? cone 2=565.2?

  4. anonymous
    • one year ago
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    Cone 1 r = 6 cm h = 6 cm r^2 = r*r = 6*6 = 36 r^2h = r*r*h = 36*6 = 216 Volume of cone = pi*r^2*h/3 = 3.14*216/3

  5. anonymous
    • one year ago
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    3.14*72 = 226.08 cm Sorry I was wrong.

  6. anonymous
    • one year ago
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    Lemme check the second one

  7. anonymous
    • one year ago
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    ok

  8. anonymous
    • one year ago
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    r^2 = 6*6 = 36 36*h = 36*!5 = 540 r^h/3 = 540/3 = 180 pi*180 = 3.14*180 = 565.2 cm :)

  9. anonymous
    • one year ago
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    do i subtract them now?

  10. anonymous
    • one year ago
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    Yes.

  11. anonymous
    • one year ago
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    i got 339.12

  12. anonymous
    • one year ago
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    Yes, That's should be correct.

  13. anonymous
    • one year ago
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    thank u

  14. anonymous
    • one year ago
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    No problem :)

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