Write an equation of a line that passes through the point (2, 3) and is parallel to the line y =3x/2+5. (5 points) y =-2/3x y = -2/3x− 7 y = 3/2x y = 3/2x+ 7

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Write an equation of a line that passes through the point (2, 3) and is parallel to the line y =3x/2+5. (5 points) y =-2/3x y = -2/3x− 7 y = 3/2x y = 3/2x+ 7

Mathematics
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@annas can you please help me?
@Loser66 can you please help?:)
The latex doesn't show. What is the given line's equation?

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sorry I'm confused?
y = .....x + 5? I don't see it
y =-2/3x y = -2/3x− 7 y = 3/2x y = 3/2x+ 7
Please, don't copy and paste. It doesn't work on my computer
oh sorry i didn't know!
y= -2/3x y= -2/3x -7 y= 3/2x y= 3/2x + 7
Want me guide or my answer?
both please!:)
the given equation is \(y = \dfrac{3}{2}x +5\) right?
yep
the slope of it is 3/2, right?
yes
hence, the required line has the same slope with it (3/2) , now you can pick either c or d.
c?
Suppose c is the correct answer, then you need put the point in, if it satisfies the equation, then c is the right one, if it doesn't, we check d
okay
to c, \(y = \dfrac{3}{2}x\), I replace the point (2,3) that is y = 3, x =2 so \(3 = \dfrac{3}{\cancel 2}\cancel 2\\3=3\) Bingo, hence c is the correct one
Then, no need to check d. C is the correct answer
thank you so very much!

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