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anonymous
 one year ago
Can someone help me with a homework problem? Simplifying complex fractions with variables. I want to learn HOW to do it, not just get the answer I have a test tomorrow.
anonymous
 one year ago
Can someone help me with a homework problem? Simplifying complex fractions with variables. I want to learn HOW to do it, not just get the answer I have a test tomorrow.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \frac{ x }{ x+2 } }{ \frac{ 1 }{ x }+\frac{ 1 }{ x+2}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have no idea how to even begin :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is kind hard to see :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The equation you mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432742093933:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is that better?messier?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First try simplifying the denominator part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do I add them together?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So \[\frac{ 2 }{ 2x+2 }\] ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, fractions can't be added like that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would the LCD be x^2 + 2x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What does LCD stand for?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Least common denominator?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So what do you get in the denominator after adding?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait with fractions the denominator doesn't change, yeah? So the denominator would still be x^2 + 2x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Or am I confusing myself?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I meant denominator of the whole expression that is givendw:1432742605895:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What would it's value be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432742696142:dw is after the LCD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sodw:1432742755723:dw ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do I simplify that at all?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Divide the numerator with that value

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And keeping x(x+2) as x(x+2) rather than multiplying would do you a little good

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, got the final answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not yet. I'm really slow with this stuff

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know if I did this right but I got\[\frac{ x^2(x + 2) }{ 2x^2 + 6x + 4 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@abdul_shabeer Is that wrong?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's not wrong, but you can still simlify it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Factorise the denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ x^2 }{ 2x + 2 }\] ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Awesome! Thank you! I think I get this now. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're welcome, and All The Best for your exam tomorrow
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