At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

I can try!

\[\frac{ \frac{ x }{ x+2 } }{ \frac{ 1 }{ x }+\frac{ 1 }{ x+2}}\]

I have no idea how to even begin :P

It is kind hard to see :D

*kinda

The equation you mean?

Yea

|dw:1432742093933:dw|

Lol

Is that better?messier?

First try simplifying the denominator part

Do I add them together?

So \[\frac{ 2 }{ 2x+2 }\] ?

No, fractions can't be added like that

Oh wait, LCD?

yes

What's LCD?

Would the LCD be x^2 + 2x?

What does LCD stand for?

Least common denominator?

Fine

So what do you get in the denominator after adding?

Or am I confusing myself?

I meant denominator of the whole expression that is given|dw:1432742605895:dw|

Ohhh

What would it's value be?

|dw:1432742696142:dw| is after the LCD

So|dw:1432742755723:dw| ?

Absolutely right

Do I simplify that at all?

Divide the numerator with that value

Kay, one sec..

And keeping x(x+2) as x(x+2) rather than multiplying would do you a little good

Oh yeah thanks

So, got the final answer?

Not yet. I'm really slow with this stuff

Take your time

I don't know if I did this right but I got\[\frac{ x^2(x + 2) }{ 2x^2 + 6x + 4 }\]

@abdul_shabeer Is that wrong?

It's not wrong, but you can still simlify it

Factorise the denominator

Oh okay

\[\frac{ x^2 }{ 2x + 2 }\] ?

Right

Awesome! Thank you! I think I get this now. :)

You're welcome, and All The Best for your exam tomorrow

Thanks :)