Can someone help me with a homework problem? Simplifying complex fractions with variables. I want to learn HOW to do it, not just get the answer- I have a test tomorrow.

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Can someone help me with a homework problem? Simplifying complex fractions with variables. I want to learn HOW to do it, not just get the answer- I have a test tomorrow.

Mathematics
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I can try!
\[\frac{ \frac{ x }{ x+2 } }{ \frac{ 1 }{ x }+\frac{ 1 }{ x+2}}\]
I have no idea how to even begin :P

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Other answers:

It is kind hard to see :D
*kinda
The equation you mean?
Yea
|dw:1432742093933:dw|
Lol
Is that better?messier?
First try simplifying the denominator part
Do I add them together?
So \[\frac{ 2 }{ 2x+2 }\] ?
No, fractions can't be added like that
Oh wait, LCD?
yes
What's LCD?
Would the LCD be x^2 + 2x?
What does LCD stand for?
Least common denominator?
Fine
So what do you get in the denominator after adding?
Wait with fractions the denominator doesn't change, yeah? So the denominator would still be x^2 + 2x?
Or am I confusing myself?
I meant denominator of the whole expression that is given|dw:1432742605895:dw|
Ohhh
What would it's value be?
|dw:1432742696142:dw| is after the LCD
So|dw:1432742755723:dw| ?
Absolutely right
Do I simplify that at all?
Divide the numerator with that value
Kay, one sec..
And keeping x(x+2) as x(x+2) rather than multiplying would do you a little good
Oh yeah thanks
So, got the final answer?
Not yet. I'm really slow with this stuff
Take your time
I don't know if I did this right but I got\[\frac{ x^2(x + 2) }{ 2x^2 + 6x + 4 }\]
@abdul_shabeer Is that wrong?
It's not wrong, but you can still simlify it
Factorise the denominator
Oh okay
\[\frac{ x^2 }{ 2x + 2 }\] ?
Right
Awesome! Thank you! I think I get this now. :)
You're welcome, and All The Best for your exam tomorrow
Thanks :)

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