anonymous
  • anonymous
3. A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Michele_Laino
  • Michele_Laino
here we have to apply the subsequent formula: \[\Large \Delta U = q\Delta V\]
Michele_Laino
  • Michele_Laino
where: \[\Delta U\] is the change in energy and: \[\Delta V\] is the requested potential difference
Michele_Laino
  • Michele_Laino
q is the cahrge, of course

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Michele_Laino
  • Michele_Laino
charge*
Michele_Laino
  • Michele_Laino
so, we have: \[\Large \Delta V = \frac{{\Delta U}}{q} = ...Volts\]
anonymous
  • anonymous
Okay, so all of the things needed in the equation are in the question? So, q = 5? ΔU = 10? Am I doing that right?
Michele_Laino
  • Michele_Laino
q= 5*10^(-6) Coulombs
anonymous
  • anonymous
Oh, okay. So then ΔV = 10? Or..
Michele_Laino
  • Michele_Laino
\[\Large \Delta V = \frac{{\Delta U}}{q} = \frac{{10}}{{5 \times {{10}^{ - 6}}}} = \frac{{10}}{5} \times {10^6} = ...Volts\]
Michele_Laino
  • Michele_Laino
@jaysabelle
anonymous
  • anonymous
So it would be \[2x10^{6}\] = volts?
anonymous
  • anonymous
@Michele_Laino
Michele_Laino
  • Michele_Laino
that's right!
Michele_Laino
  • Michele_Laino
your answer is correct!
anonymous
  • anonymous
Really? Thank you!

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