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anonymous
 one year ago
3. A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved?
anonymous
 one year ago
3. A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved?

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here we have to apply the subsequent formula: \[\Large \Delta U = q\Delta V\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1where: \[\Delta U\] is the change in energy and: \[\Delta V\] is the requested potential difference

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1q is the cahrge, of course

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so, we have: \[\Large \Delta V = \frac{{\Delta U}}{q} = ...Volts\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so all of the things needed in the equation are in the question? So, q = 5? ΔU = 10? Am I doing that right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1q= 5*10^(6) Coulombs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, okay. So then ΔV = 10? Or..

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large \Delta V = \frac{{\Delta U}}{q} = \frac{{10}}{{5 \times {{10}^{  6}}}} = \frac{{10}}{5} \times {10^6} = ...Volts\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it would be \[2x10^{6}\] = volts?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1your answer is correct!
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