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anonymous

  • one year ago

3. A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved?

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  1. Michele_Laino
    • one year ago
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    here we have to apply the subsequent formula: \[\Large \Delta U = q\Delta V\]

  2. Michele_Laino
    • one year ago
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    where: \[\Delta U\] is the change in energy and: \[\Delta V\] is the requested potential difference

  3. Michele_Laino
    • one year ago
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    q is the cahrge, of course

  4. Michele_Laino
    • one year ago
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    charge*

  5. Michele_Laino
    • one year ago
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    so, we have: \[\Large \Delta V = \frac{{\Delta U}}{q} = ...Volts\]

  6. anonymous
    • one year ago
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    Okay, so all of the things needed in the equation are in the question? So, q = 5? ΔU = 10? Am I doing that right?

  7. Michele_Laino
    • one year ago
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    q= 5*10^(-6) Coulombs

  8. anonymous
    • one year ago
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    Oh, okay. So then ΔV = 10? Or..

  9. Michele_Laino
    • one year ago
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    \[\Large \Delta V = \frac{{\Delta U}}{q} = \frac{{10}}{{5 \times {{10}^{ - 6}}}} = \frac{{10}}{5} \times {10^6} = ...Volts\]

  10. Michele_Laino
    • one year ago
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    @jaysabelle

  11. anonymous
    • one year ago
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    So it would be \[2x10^{6}\] = volts?

  12. anonymous
    • one year ago
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    @Michele_Laino

  13. Michele_Laino
    • one year ago
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    that's right!

  14. Michele_Laino
    • one year ago
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    your answer is correct!

  15. anonymous
    • one year ago
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    Really? Thank you!

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