## anonymous one year ago 3. A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved?

1. Michele_Laino

here we have to apply the subsequent formula: $\Large \Delta U = q\Delta V$

2. Michele_Laino

where: $\Delta U$ is the change in energy and: $\Delta V$ is the requested potential difference

3. Michele_Laino

q is the cahrge, of course

4. Michele_Laino

charge*

5. Michele_Laino

so, we have: $\Large \Delta V = \frac{{\Delta U}}{q} = ...Volts$

6. anonymous

Okay, so all of the things needed in the equation are in the question? So, q = 5? ΔU = 10? Am I doing that right?

7. Michele_Laino

q= 5*10^(-6) Coulombs

8. anonymous

Oh, okay. So then ΔV = 10? Or..

9. Michele_Laino

$\Large \Delta V = \frac{{\Delta U}}{q} = \frac{{10}}{{5 \times {{10}^{ - 6}}}} = \frac{{10}}{5} \times {10^6} = ...Volts$

10. Michele_Laino

@jaysabelle

11. anonymous

So it would be $2x10^{6}$ = volts?

12. anonymous

@Michele_Laino

13. Michele_Laino

that's right!

14. Michele_Laino