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anonymous

  • one year ago

Basic calc question. I am given the derivative and the value of y at a given x value, can i find this?

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  1. anonymous
    • one year ago
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    I know g(5)=-3 and g(5)'=6. I am asked to find the derivative of f(5). I am told f(x)=[g(x)]^3 . Is this capable of being solved, and if so how.

  2. rational
    • one year ago
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    differentiate using chain rule

  3. rational
    • one year ago
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    f(x) = [g(x)]^3 f'(x) = ?

  4. anonymous
    • one year ago
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    I guessed that but what is the derivative of a floating exponent. Im sorry if im typing slowly for some reason this site is killing my computer.

  5. anonymous
    • one year ago
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    6*3*-3^2?

  6. rational
    • one year ago
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    use this \[\frac{d}{dx}x^n ~=~n*x^{n-1}\]

  7. anonymous
    • one year ago
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    Yeah thats like the first rule of differntation you learn, but does it still appy without a varible x?

  8. rational
    • one year ago
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    variables are just dummy

  9. rational
    • one year ago
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    \[\large \frac{d}{d\clubsuit} \clubsuit^n ~= ~n*\clubsuit^{n-1} \]

  10. anonymous
    • one year ago
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    XD

  11. anonymous
    • one year ago
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    S0 6*3*(-3)^2 would fit that or not?

  12. rational
    • one year ago
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    \[ f(x) = [g(x)]^3\] \[f'(x) = 3*[g(x)]^{3-1} * \color{red}{g'(x)}\]

  13. rational
    • one year ago
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    plugin \(x=5\)

  14. rational
    • one year ago
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    6*3*(-3)^2 looks good!

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