anonymous
  • anonymous
Dr. Oguz counted the number of cubs in 10 tiger cub litters and then arranged the numbers from smallest to largest. The numbers of cubs in each litter were 1, 1, 2, 2, 3, 3, 3, 4, 5, and 6. The mean of these measurements is 3. What is the mean absolute deviation? A. 1.2 B. 1.5 C. 2 D. 12
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
tkhunny
  • tkhunny
Do not post questions with no work shown. You should calculate the Absolute Deviation from 3 for each item.
anonymous
  • anonymous
@tkhunny I don't know how

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anonymous
  • anonymous
Let's see...I think it's C...But I'm probably wrong..
tkhunny
  • tkhunny
Hogwash. |1-3| = 2 |2-3| = 1 |2-3| = 1 |3-3| = 0 |3-3| = 0 |3-3| = 0 |4-3| = 1 |5-3| = 2 |6-3| = 3 You can't do that?
anonymous
  • anonymous
@tkhunny I didnt know it was that easy
anonymous
  • anonymous
@tkhunny Thanks
tkhunny
  • tkhunny
I knew you could do it. Now add them up and divide by however many there are. Mean, Absolute Deviation. Done.
anonymous
  • anonymous
10
tkhunny
  • tkhunny
That's the TOTAL of Absolute Deviations. Now the MEAN Absolute Deviation...
anonymous
  • anonymous
How do you get it @tkhunny
tkhunny
  • tkhunny
Asked and answered. Mean --- Average --- Divide by something...
anonymous
  • anonymous
3/10 is 0.3
tkhunny
  • tkhunny
We already know the MEAN of the data. That's 3. We already added things up and divided by 9. This gave 3, the Mean or Average. We need the Mean Absolute Deviation. Find the total of the absolute deviations. You did that. 10. Now divide by what to get the MEAN absolute deviation?

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