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anonymous

  • one year ago

Dr. Oguz counted the number of cubs in 10 tiger cub litters and then arranged the numbers from smallest to largest. The numbers of cubs in each litter were 1, 1, 2, 2, 3, 3, 3, 4, 5, and 6. The mean of these measurements is 3. What is the mean absolute deviation? A. 1.2 B. 1.5 C. 2 D. 12

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  1. anonymous
    • one year ago
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    @tkhunny

  2. tkhunny
    • one year ago
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    Do not post questions with no work shown. You should calculate the Absolute Deviation from 3 for each item.

  3. anonymous
    • one year ago
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    @tkhunny I don't know how

  4. anonymous
    • one year ago
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    Let's see...I think it's C...But I'm probably wrong..

  5. tkhunny
    • one year ago
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    Hogwash. |1-3| = 2 |2-3| = 1 |2-3| = 1 |3-3| = 0 |3-3| = 0 |3-3| = 0 |4-3| = 1 |5-3| = 2 |6-3| = 3 You can't do that?

  6. anonymous
    • one year ago
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    @tkhunny I didnt know it was that easy

  7. anonymous
    • one year ago
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    @tkhunny Thanks

  8. tkhunny
    • one year ago
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    I knew you could do it. Now add them up and divide by however many there are. Mean, Absolute Deviation. Done.

  9. anonymous
    • one year ago
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    10

  10. tkhunny
    • one year ago
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    That's the TOTAL of Absolute Deviations. Now the MEAN Absolute Deviation...

  11. anonymous
    • one year ago
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    How do you get it @tkhunny

  12. tkhunny
    • one year ago
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    Asked and answered. Mean --- Average --- Divide by something...

  13. anonymous
    • one year ago
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    3/10 is 0.3

  14. tkhunny
    • one year ago
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    We already know the MEAN of the data. That's 3. We already added things up and divided by 9. This gave 3, the Mean or Average. We need the Mean Absolute Deviation. Find the total of the absolute deviations. You did that. 10. Now divide by what to get the MEAN absolute deviation?

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