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anonymous
 one year ago
An airtrack glider of mass 0.25 kg moving at 0.60 m/s collides with and sticks to a glider of mass 0.50 kg at rest. How much kinetic energy is converted into other forms of energy as a direct result of this collision?
A. 0.030 J
B. 0.045 J
C. 0.015 J
D. 0.060 J
***not sure at all! :( Thank you!! :D
anonymous
 one year ago
An airtrack glider of mass 0.25 kg moving at 0.60 m/s collides with and sticks to a glider of mass 0.50 kg at rest. How much kinetic energy is converted into other forms of energy as a direct result of this collision? A. 0.030 J B. 0.045 J C. 0.015 J D. 0.060 J ***not sure at all! :( Thank you!! :D

This Question is Closed

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here we have to apply the conservation of momentum, so we can write: \[\Large {m_1}{v_1} = \left( {{m_1} + {m_2}} \right)u\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1where m_1= 0.25 Kg, m_2=0.50 Kg, and v_1=0.60 m/sec

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1u is the final speed of the system particle1+ particle2

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have to find what is u: \[\Large u = \frac{{{m_1}{v_1}}}{{{m_1} + {m_2}}} = ...m/\sec \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, so i plug in like this? (0.25*0.60)=(0.25+0.50)u so like this? 0.15=0.75u u=0.2 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh wait... it is 0.2, correct? the value of u?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1that's right u=0.2 m/sec

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay! what happens next?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1Now the final kinetic energy is: \[\Large {E_f} = \frac{1}{2}\left( {{m_1} + {m_2}} \right){u^2} = ...Joules\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay! so 1/2(0.25+0.50)0.2^2 = 0.015 J ? so the answer is 0.015 J? :O

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1whereas the initial kinetic energy is: \[\Large {E_i} = \frac{1}{2}{m_1}v_1^2 = ...Joules\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ahh so it would be 1/2(0.25+0.5^2)? so 0.25 is the initial kinetic energy?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I got 0.045 Joules

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large {E_i} = \frac{1}{2}{m_1}v_1^2 = \frac{1}{2} \times 0.25 \times {\left( {0.6} \right)^2} = ...Joules\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh yes 0.045 sorry, i plugged in the wrong thing! wait so for this problem, i now have to do this to find the answer? 0.0450.015=0.030 J ? and that would be this problem's final solution? :O

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! That's right!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay!! and so this problem is completed now? :O

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! We have finished!
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