Factor. v2 – 36 A. (v + 6)(v – 6) B. (v – 6)2 C. (v2 – 6)2 D. (v – 6)(v – 6)

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Factor. v2 – 36 A. (v + 6)(v – 6) B. (v – 6)2 C. (v2 – 6)2 D. (v – 6)(v – 6)

Mathematics
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Any ideas? Hint: a difference of squares can be factored into the sum of two numbers times their difference.
Hey! Ok first we write 36 as a square in order to express x2-36 as a difference squares so what do we get?
so we are just writing 36 as a square

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I barley started learning this, since a square is 4 is it 36/4? Im just taking a guess?
v^2 — 36 = v^2 — 6^2
Well it was like this 6^2 before right? so they put it into this 36 b.c 6^2=36 so now they want it back to 6^2 @ninowletonzalez06
you get it @ninowletonzalez06
so if we put it back to 6^2 we get \[v ^{2}-6^{2}\]
Have you studied the FOIL method?
so im thinking it will be A or D?
Good so net we factor the difference of two squares
next*
so we factor the difference of two square and what do we get
since the symbol is subtraction it should be D since both of the signs are (-)
Nope its not b.c we factoring the difference
your on the right track :D
can you explain on the drawing tool?
|dw:1432756259898:dw|
Try using the distributive property.
|dw:1432756300805:dw|
So what do we do next?
|dw:1432745539339:dw|
Yea its V2 but we factored it out so do the same for the other and yes it 6^2 sorry :D
|dw:1432745679759:dw|
(v+6)•(v-6) =(v+6)v-(v+6)6
Ok lets try this :D Lets use difference of squares which the formula is \[a ^{2}-b ^{2}=(a+b)(a-b)\]
Plug it in @ninowletonzalez06
(v+6)(v-6)
Correct
Great job :D
so A is your answer!
Anytime you get this sort of question just the formula i gave above and Yes A is correct :D
Determine if the expression is a perfect square and if it is, factor it. a2 – 8a – 16 A. (4a + 1)2 B. (a + 4)(a – 4) C. (a – 4)(a – 4) D. not a perfect square
~Glad to had help and have a great day :D
Oh one question per post :D
i have a couple of more questions, do you mind helping?
Sure

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