## anonymous one year ago question inside!! :)

1. anonymous

|dw:1432745418519:dw|

2. Michele_Laino

we can consider the root mean quadratic speed of a molecule of a gas, which is given by the subsequent formula: $\Large {v_{RMQ}} = \sqrt {\frac{{3RT}}{M}}$

3. Michele_Laino

where R is the gas constant, namely R=8.31 J/Kelvin, and M is the molecular mass of our gas. T is the gas temperature of course, measured in Kelvin

4. anonymous

okay! so how can we figure out which object (A,B,C or D) moves the fastest? what do we plug in?

5. Michele_Laino

I think that we can consider only the temperature, since the molecular mass of those gases are similar each other

6. Michele_Laino

namely, we have: $\Large {M_A} \simeq {M_B} \simeq {M_C} \simeq {M_D}$

7. anonymous

okay!! so 3*temperature? would that mean object D moves the fastest since the solution would be the largest?

8. Michele_Laino

yes! that's right!

9. anonymous

ooh yay!! thank you:D

10. Michele_Laino

thank you!! :D