A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
The amount of heat needed to raise 250 g of a substance by 15 K is 2,930 J. What is the specific heat of the substance (J/(kg*K))?
A. 0.78
B. 11,000
C. 780
D. 1.1 × 10^7
**not 100% sure, but is this choice C? 780?
anonymous
 one year ago
The amount of heat needed to raise 250 g of a substance by 15 K is 2,930 J. What is the specific heat of the substance (J/(kg*K))? A. 0.78 B. 11,000 C. 780 D. 1.1 × 10^7 **not 100% sure, but is this choice C? 780?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432746745005:dw the equation... in case i didn't write it clearly :P

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here we have to use this formula: \[\Large Q = cm\Delta T\] Q is the heat , c is the specific heat, and T is the absolute temperature

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay! so what would be plugged in? :/

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so, we can write: \[\Large c = \frac{Q}{{m\Delta T}} = ...\frac{{Joules}}{{Kg \times Kelvin}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay! so 2930/(kg*15)? is that right? and solve for kg?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1no, we have to compute this: \[\Large c = \frac{Q}{{m\Delta T}} = \frac{{2930}}{{0.250 \times 15}} = ...\frac{{Joules}}{{Kg \times Kelvin}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh okay!! so we get 781.333333 so about 780?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.