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anonymous

  • one year ago

The amount of heat needed to raise 250 g of a substance by 15 K is 2,930 J. What is the specific heat of the substance (J/(kg*K))? A. 0.78 B. 11,000 C. 780 D. 1.1 × 10^7 **not 100% sure, but is this choice C? 780?

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  1. anonymous
    • one year ago
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    |dw:1432746745005:dw| the equation... in case i didn't write it clearly :P

  2. Michele_Laino
    • one year ago
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    here we have to use this formula: \[\Large Q = cm\Delta T\] Q is the heat , c is the specific heat, and T is the absolute temperature

  3. anonymous
    • one year ago
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    okay! so what would be plugged in? :/

  4. Michele_Laino
    • one year ago
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    so, we can write: \[\Large c = \frac{Q}{{m\Delta T}} = ...\frac{{Joules}}{{Kg \times Kelvin}}\]

  5. anonymous
    • one year ago
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    okay! so 2930/(kg*15)? is that right? and solve for kg?

  6. Michele_Laino
    • one year ago
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    no, we have to compute this: \[\Large c = \frac{Q}{{m\Delta T}} = \frac{{2930}}{{0.250 \times 15}} = ...\frac{{Joules}}{{Kg \times Kelvin}}\]

  7. anonymous
    • one year ago
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    ohh okay!! so we get 781.333333 so about 780?

  8. Michele_Laino
    • one year ago
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    that's right!!

  9. anonymous
    • one year ago
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    yay!! thank you:D

  10. Michele_Laino
    • one year ago
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    :D

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