## A community for students. Sign up today

Here's the question you clicked on:

## anonymous one year ago The amount of heat needed to raise 250 g of a substance by 15 K is 2,930 J. What is the specific heat of the substance (J/(kg*K))? A. 0.78 B. 11,000 C. 780 D. 1.1 × 10^7 **not 100% sure, but is this choice C? 780?

• This Question is Closed
1. anonymous

|dw:1432746745005:dw| the equation... in case i didn't write it clearly :P

2. Michele_Laino

here we have to use this formula: $\Large Q = cm\Delta T$ Q is the heat , c is the specific heat, and T is the absolute temperature

3. anonymous

okay! so what would be plugged in? :/

4. Michele_Laino

so, we can write: $\Large c = \frac{Q}{{m\Delta T}} = ...\frac{{Joules}}{{Kg \times Kelvin}}$

5. anonymous

okay! so 2930/(kg*15)? is that right? and solve for kg?

6. Michele_Laino

no, we have to compute this: $\Large c = \frac{Q}{{m\Delta T}} = \frac{{2930}}{{0.250 \times 15}} = ...\frac{{Joules}}{{Kg \times Kelvin}}$

7. anonymous

ohh okay!! so we get 781.333333 so about 780?

8. Michele_Laino

that's right!!

9. anonymous

yay!! thank you:D

10. Michele_Laino

:D

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy