anonymous
  • anonymous
If 50 g of liquid water [C = 4,180 J/(kg*K)] changes temperature in a calorimeter from 298 K to 348 K, then how much heat is transferred? A. 10.5 J B. 10.5 kJ C. 72.7 J D. 100 kJ **Not sure about this one! thank you:)
Physics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Michele_Laino
  • Michele_Laino
here we have to apply this formula: \[\Large Q = cm\Delta T = 4180 \times 0.05 \times \left( {348 - 298} \right) = ...Joules\]
anonymous
  • anonymous
okay!! so we get 10450 Joules? so about 10.5 kJ ?
Michele_Laino
  • Michele_Laino
correct!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yay!! :D thanks!!! :D
Michele_Laino
  • Michele_Laino
thanks!!!!! :D

Looking for something else?

Not the answer you are looking for? Search for more explanations.