anonymous
  • anonymous
solve ln 5+ln (2x)=5 round your answer to the nearest hundredth. Please help.
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Nnesha
  • Nnesha
write in single ln form product rule \[\large \rm ln x + \ln y = \ln ( x \times y )\]
anonymous
  • anonymous
Could you go on? because I'm still confused.
Nnesha
  • Nnesha
let's say x represent 5 and 2x represent y how would you condense ln in single ln form ? just like in this equation \[\large \rm ln x + \ln y = \ln ( x \times y )\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I keep getting 1/2
Nnesha
  • Nnesha
\[\large \rm ln x + \ln y = \ln ( x \times y )\] \[\large\rm ln 5 + \ln (2x) = ?\]
Nnesha
  • Nnesha
show your work how did you get 1/2 ?
anonymous
  • anonymous
Well it goes like ln(2x)=−5+5 ln(2x)=0 (e)0=2x e0=2x 1=2x 2x=1 x=1/2
Nnesha
  • Nnesha
alright first step is wrong why did you subtract 5 ?
Nnesha
  • Nnesha
it's ln 5 at left side not just 5
anonymous
  • anonymous
My choices are 1.1484 2.11.17 3.71.71 4.0.02 also since Since 5 does not contain the variable to solve for, we move it to the right-hand side of the equation by subtracting 5 from both sides. If I'm wrong can you direct me in the direction of the right answer by showing me how to do it?
Nnesha
  • Nnesha
alright nope you can't subtract 5 bec it's ln(5)
anonymous
  • anonymous
Okay, well can you show me, please ?
Nnesha
  • Nnesha
first of all apply product property \[\large \rm ln x + \ln y = \ln ( x \times y )\] \[\large\rm ln 5 + \ln (2x) = ln(5 \times2x) \] there is a plus sign so you have to apply product property
Nnesha
  • Nnesha
\[\huge\rm ln (5 \times 2x) =5\] now take e both side do it let me know what yo uget
anonymous
  • anonymous
3.85244
anonymous
  • anonymous
Wait I did something wrong
Nnesha
  • Nnesha
yes try again :-)
anonymous
  • anonymous
Sorry, I'm not sure what to do. I'm pretty brain dead because I have been working on my math final since like 7 am.
Nnesha
  • Nnesha
math final ?
Nnesha
  • Nnesha
is it from a test ?? :-)
anonymous
  • anonymous
Mhm, I have about 16 questions left out of 50.
Nnesha
  • Nnesha
sorry...
kidrah69
  • kidrah69
We help study for tests we DO NOT help you ON the test. Please go find a diffrent website to cheat from because we will not help you with a test refer the the Terms and conditions which YOU agreed to before you decided to come to this site. thanks.
EclipsedStar
  • EclipsedStar
http://goo.gl/NJQwpm
TheSmartOne
  • TheSmartOne
http://www.nig.gr/brJ
anonymous
  • anonymous
I didn't feel like it was cheating, I was just asking for explanation rather than the answer, you know?
anonymous
  • anonymous
Well I'll close the question, I wasn't aware, sorry.
kidrah69
  • kidrah69
Would you teacher want to see what U know or what we know?

Looking for something else?

Not the answer you are looking for? Search for more explanations.