- anonymous

solve ln 5+ln (2x)=5 round your answer to the nearest hundredth. Please help.

- schrodinger

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- Nnesha

write in single ln form product rule \[\large \rm ln x + \ln y = \ln ( x \times y )\]

- anonymous

Could you go on? because I'm still confused.

- Nnesha

let's say x represent 5
and 2x represent y
how would you condense ln in single ln form ?
just like in this equation \[\large \rm ln x + \ln y = \ln ( x \times y )\]

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## More answers

- anonymous

I keep getting 1/2

- Nnesha

\[\large \rm ln x + \ln y = \ln ( x \times y )\]
\[\large\rm ln 5 + \ln (2x) = ?\]

- Nnesha

show your work how did you get 1/2 ?

- anonymous

Well it goes like ln(2x)=−5+5
ln(2x)=0
(e)0=2x
e0=2x
1=2x
2x=1
x=1/2

- Nnesha

alright first step is wrong
why did you subtract 5 ?

- Nnesha

it's ln 5 at left side
not just 5

- anonymous

My choices are
1.1484
2.11.17
3.71.71
4.0.02
also since Since 5 does not contain the variable to solve for, we move it to the right-hand side of the equation by subtracting 5 from both sides. If I'm wrong can you direct me in the direction of the right answer by showing me how to do it?

- Nnesha

alright nope you can't subtract 5
bec it's ln(5)

- anonymous

Okay, well can you show me, please ?

- Nnesha

first of all apply product property
\[\large \rm ln x + \ln y = \ln ( x \times y )\]
\[\large\rm ln 5 + \ln (2x) = ln(5 \times2x) \]
there is a plus sign so you have to apply product property

- Nnesha

\[\huge\rm ln (5 \times 2x) =5\]
now take e both side
do it let me know what yo uget

- anonymous

3.85244

- anonymous

Wait I did something wrong

- Nnesha

yes try again :-)

- anonymous

Sorry, I'm not sure what to do. I'm pretty brain dead because I have been working on my math final since like 7 am.

- Nnesha

math final ?

- Nnesha

is it from a test ?? :-)

- anonymous

Mhm, I have about 16 questions left out of 50.

- Nnesha

sorry...

- kidrah69

We help study for tests we DO NOT help you ON the test. Please go find a diffrent website to cheat from because we will not help you with a test refer the the Terms and conditions which YOU agreed to before you decided to come to this site. thanks.

- EclipsedStar

http://goo.gl/NJQwpm

- TheSmartOne

http://www.nig.gr/brJ

- anonymous

I didn't feel like it was cheating, I was just asking for explanation rather than the answer, you know?

- anonymous

Well I'll close the question, I wasn't aware, sorry.

- kidrah69

Would you teacher want to see what U know or what we know?

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