anonymous
  • anonymous
Please Check and see if they are correct (Will give Medal!):http://snag.gy/8IRIW.jpg
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

triciaal
  • triciaal
|dw:1432753778342:dw|
triciaal
  • triciaal
|dw:1432753938645:dw|
anonymous
  • anonymous
Thank you I knew I was forgetting to do something on that one. Thx you for show me ^^

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

triciaal
  • triciaal
the 2nd might be an AP a = 9 and d = 0.75 find when n = 11
anonymous
  • anonymous
sorry >< what do you mean by AP ?
triciaal
  • triciaal
arithmetic progression a the first term d the common difference
anonymous
  • anonymous
ah, thank you. n is like the the value amount?
anonymous
  • anonymous
For example will this equation be : 9+0.75n
triciaal
  • triciaal
|dw:1432754434566:dw|
anonymous
  • anonymous
oh, that would make sense><
triciaal
  • triciaal
here n = 11, a = 9 d = 0.75
triciaal
  • triciaal
you are welcome
anonymous
  • anonymous
16.50 ? and Thank you so much :)
anonymous
  • anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.