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  • one year ago

In watermelons, bitter fruit (B) is dominant over sweet fruit (b), and yellow spots(S) are dominant over no spots (s). A homozygous plant that has bitter fruit and yellow spots is crossed with a homozygous plant that has sweet fruit and no spots. The F1 are intercrossed to produce F2. What will be the phenotypic ratios in F2? I don't understand how to choose the possible gametes for the f2 generation to set up my punnett square. Please help!

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  1. anonymous
    • one year ago
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    P - BBSS x bbss F1 - BbSs x BbSs a. 9 (bitter w/ spots): 3 (bitter w/ no spots) : 3 (sweet w/ spots) : 1 (sweet w/ no spots) b. 100% bitter with spots . BBSS - 1/4; BbSs - 1/4; BBSs - 1/4; BbSS- 1/4 c. BbSs - Bitter w/ spots - 1/4 ; Bbss - bitter w/ no spots - 1/4 ; bbSs - sweet w/ spots - 1/4 ; bbss - sweet with no spots - 1/4

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