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do you know how to get projection of one vector on other?
tried to solve this?

Projection of vector a on vector b is
\(\LARGE \dfrac{a.b}{|b|}\)

So it would start off like this?....
(1.6i + 3.3j) (-2.1i -0.5j)
= -3.36 -6.93 -1.65 -0.8

note that
\(i . j \)
and \(j.i\)
both = 0
as they are perpendicular vectors!

so you'll only have
1.6*(-2.1) + 3.3*(-0.5) = ...

Give me just a second on the division. I think I did something wrong.

1.6*(-2.1) + 3.3*(-0.5) = -5.01

So the numerator is -5.01
and the denominator is about 2.16
and you would divide that?

thats right
that will give you the magnitude of the projection vector :)

About -2.32

Wouldn't "b" be the direction? (-2.1i -0.5j)

unit vector along v = v/ |v|
and we already know |v| = 2.16

(-2.1i -0.5j)/ 2.16
Would that be (-0.97i -0.23)?

what do u get after multiplying that with -2.32?

-2.32 (-0.97i -0.23)
= (-2.25i -0.53j)

two negatives become positive!
and you can approximate 2.25 to 2.3 and 0.53 to 0.5 :)

-2.32 * -0.97 = +2.3
-2.32 * -0.23 = +0.5

yes, correct!
good work :)

Thank you for your help. :)

most welcome ^_^