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alurahenderson

  • one year ago

WILL MEDAL What is the area of the figure?

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  1. jojo12g
    • one year ago
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    wheres the piicture

  2. anonymous
    • one year ago
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    wheres the figure?

  3. KaylaRdz0405
    • one year ago
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    the figure?

  4. anonymous
    • one year ago
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    k

  5. alurahenderson
    • one year ago
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    Sorry I thought I sent it

  6. anonymous
    • one year ago
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    its fine lol :)

  7. anonymous
    • one year ago
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    DO you know how to find the area of triangles and/or trapezoids?

  8. anonymous
    • one year ago
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    do 17 times 14 and then 18 times 12

  9. alurahenderson
    • one year ago
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    Yes I do

  10. alurahenderson
    • one year ago
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    b x h /2 ?

  11. anonymous
    • one year ago
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    And which one is that for?

  12. anonymous
    • one year ago
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    well, with this figure you can break it down...so if you know how to find the area of triangles and trapezoids, its not as hard as it looks :)

  13. anonymous
    • one year ago
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    yes

  14. alurahenderson
    • one year ago
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    How would I find the width? {I am horrible with math sorry}

  15. alurahenderson
    • one year ago
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    ???

  16. alurahenderson
    • one year ago
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    238 and 216

  17. anonymous
    • one year ago
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    hm? what do you mean?

  18. alurahenderson
    • one year ago
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    Because if i break it up the shape at the top would need a height, sorry I meant hieght not width

  19. alyssa_xo
    • one year ago
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    you have the height of part of the whole shape and and the entire complex shape the trapezoid is just 17-12

  20. alurahenderson
    • one year ago
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    2?

  21. alyssa_xo
    • one year ago
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    http://puu.sh/i2KkC/b0aa4001c8.png nope

  22. alyssa_xo
    • one year ago
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    notice that the height of the triangles is 12 the whole shape's height is 17 that means if you extend the height of the triangle to the end of the shape you get \(12+x=17\)

  23. alurahenderson
    • one year ago
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    5

  24. alurahenderson
    • one year ago
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    I don't know why I put 2

  25. alyssa_xo
    • one year ago
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    |dw:1432754292136:dw| area of a trapezoid = \(\dfrac{a+b}{2}h=\dfrac{14+18}{2}*5=\dfrac{32}{2}*5=16*5=80\) next, we find the area of the triangles

  26. alurahenderson
    • one year ago
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    Okay, is 9 the width because it's half of the bottom of the top shape?

  27. alyssa_xo
    • one year ago
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    that isn't necessary as we'd be adding up the 2 triangles anyways. recall that \(Area(\Delta)=\dfrac{bh}{2}\)

  28. alurahenderson
    • one year ago
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    oh

  29. alyssa_xo
    • one year ago
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    if you don't believe me you can break it up or do it as a whole.|dw:1432754774085:dw|

  30. alurahenderson
    • one year ago
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    oh! okay see I didn't understand what you were saying at first I get it now it would be 108?

  31. alyssa_xo
    • one year ago
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    mhm 108+the other area is the whole thing

  32. alurahenderson
    • one year ago
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    216

  33. alyssa_xo
    • one year ago
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    hm? I thought the other area was 80

  34. alurahenderson
    • one year ago
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    oh im sorry I thought you meant not to half to triangles and add those

  35. alurahenderson
    • one year ago
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    188

  36. alyssa_xo
    • one year ago
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    oh, you added up the triangle twice the reason I drew it out was because I wanted to demonstrate that you could either take the area of the whole triangle (0.5*12*18=108) or you could do the 2 triangles (0.5*12*9)+(0.5*12*9)=108

  37. alyssa_xo
    • one year ago
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    yeah

  38. alurahenderson
    • one year ago
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    Okay, Thank you very much :}

  39. alyssa_xo
    • one year ago
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    you're welcome ;)

  40. alyssa_xo
    • one year ago
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    :) whoops

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