- anonymous

please help me solve this
a=x+y+z/3
a. y = a - 3x - z
b. y = a - x - 3z
c. y = 3a - x - z

- jamiebookeater

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- FibonacciChick666

If, a,x and z were numbers, could you find y?

- anonymous

\[\frac{ x+y+z }{ 3 } it looks like this

- anonymous

|dw:1432755045660:dw|

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## More answers

- FibonacciChick666

I assumed from the answer choices that was the problem, but you still have not answered, if a,z, and x were just numbers instead of variables, could you find y?

- anonymous

i dont know how

- FibonacciChick666

ok, so can you tell me the order of operations?

- anonymous

i really know nothing about this thats why i need help

- FibonacciChick666

Well, then at least google the order of operations. You should have learned that in 5th or 6th grade.

- anonymous

divide is first

- FibonacciChick666

I would like to know the whole order, for example, people like to use PEMDAS to remember, can you tell me what each letter stands for?

- anonymous

parenthasis exponets multiplication division adition subtraction

- FibonacciChick666

alright, so it is important to remember the order of operations because when you solve for a variable, you just reverse it. So we will do SadMep

- FibonacciChick666

So, first we write what the question actually means
\[a=\frac{(x+y+z)}{3}\] Now, we reverse the order of operations and ask ourselves, is there any subtraction?

- anonymous

no subtraction

- anonymous

there is addition

- FibonacciChick666

but it is inside parentheses right? So we have to wait

- FibonacciChick666

so now, keep going, what comes after addition when we reverse the order of ops?

- anonymous

divition

- FibonacciChick666

right, so what is the opposite of division?

- anonymous

multiplication

- FibonacciChick666

good, so if we are dividing by 3, to undo it, we need to multiply both sides by 3, can you tell me what you get?

- anonymous

3a=x+y+z

- FibonacciChick666

nice, so now, restart your reversal of the order of ops

- FibonacciChick666

any subtraction?

- anonymous

no subtraction

- FibonacciChick666

so what comes next?

- anonymous

adition

- FibonacciChick666

is there any?

- anonymous

yes x+y+z

- FibonacciChick666

ok, so what are we trying to get by itself?

- FibonacciChick666

and how do we undo addition?

- anonymous

do we subtracts y and z

- FibonacciChick666

well, we want y so we will leave it. If we subtracted y and z from bothe sides, we'd find x not y. So what do we need to subtraact from both sides?

- anonymous

z and x?

- FibonacciChick666

yea, and what do you get?

- anonymous

3a=y

- FibonacciChick666

no, remember you have to do it to both sides

- anonymous

-3?

- FibonacciChick666

nah, just write the whole thing out. you are here: \[3a=x+y+z\]

- FibonacciChick666

so what are you doing?

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