BloomLocke367
  • BloomLocke367
Use the Law of Sines. Find m
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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BloomLocke367
  • BloomLocke367
|dw:1432755865708:dw|
sparrow2
  • sparrow2
m
BloomLocke367
  • BloomLocke367
yes, the measure of angle C.

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BloomLocke367
  • BloomLocke367
@Nnesha @perl @Preetha
sparrow2
  • sparrow2
so we need ti find sin24
BloomLocke367
  • BloomLocke367
but it's not a right triangle.
BloomLocke367
  • BloomLocke367
does that still apply?
BloomLocke367
  • BloomLocke367
I don't understand the Law of Sines
sparrow2
  • sparrow2
yes it still apply just write sin24
BloomLocke367
  • BloomLocke367
okay
BloomLocke367
  • BloomLocke367
I got 0.4067....
BloomLocke367
  • BloomLocke367
@sparrow2
sparrow2
  • sparrow2
so just enter this in the formula and then round nearest tenth
BloomLocke367
  • BloomLocke367
what formula?
BloomLocke367
  • BloomLocke367
@perl
sparrow2
  • sparrow2
law of sines
BloomLocke367
  • BloomLocke367
I don't know the formula.
sparrow2
  • sparrow2
162/sinc=77/sin24
sparrow2
  • sparrow2
then find sinc and look at the table to the relevant angle
BloomLocke367
  • BloomLocke367
what table? and I'm very confused right now..
sparrow2
  • sparrow2
values of trig function at different angle
perl
  • perl
Does it make sense up to here $$ \Large \frac{\sin 24^o}{77}= \frac{\sin C}{162} $$
BloomLocke367
  • BloomLocke367
why is it like that?
perl
  • perl
here is a diagram of the law of sines http://www.mathworksheetsgo.com/sheets/trigonometry/advanced/law-of-sines-and-cosines/images/picture-law-of-sines-formula.jpg
BloomLocke367
  • BloomLocke367
ohhhh, yes that makes sense.
perl
  • perl
so we are using just two parts of the three part ratio
perl
  • perl
you can do that since they are equal
BloomLocke367
  • BloomLocke367
okay.
perl
  • perl
we don't know `sin B` and `b` anyway at this point , yet
BloomLocke367
  • BloomLocke367
and we have to solve for C?
perl
  • perl
$$ \Large{ \frac{\sin 24^o}{77}= \frac{\sin C}{162} \\~\\ \iff \\~\\ \sin 24^o \times 162 = 77 \times \sin C \\~\\ \iff \\~\\ \frac{\sin 24^o \times 162}{77} = \sin C }$$
BloomLocke367
  • BloomLocke367
okay. and how do we isolate C?
perl
  • perl
$$ \Large{ \frac{\sin 24^o}{77}= \frac{\sin C}{162} \\~\\ \iff \\~\\ \sin 24^o \times 162 = 77 \times \sin C \\~\\ \iff \\~\\ \frac{\sin 24^o \times 162}{77} = \sin C \\~\\ \iff \\~\\ \sin^{-1} \left( \frac{\sin 24^o \times 162}{77} \right)= C }$$
BloomLocke367
  • BloomLocke367
that's what I thought, okay.
perl
  • perl
make sure you are in degree mode if you are using a TI 83/84/85 calculator
BloomLocke367
  • BloomLocke367
I got 58.8
BloomLocke367
  • BloomLocke367
is that right?
perl
  • perl
yes :)
perl
  • perl
|dw:1432757526103:dw|
BloomLocke367
  • BloomLocke367
Oh, wow. Thank you so much! I might need your help later, but I don't know. \(\Huge\rlap{\tt\color{teal}{Thank~you!}}{\;\tt\color{lime}{Thank~you!}}\)
perl
  • perl
Now try to 'solve' the triangle (find all side lengths and angles). You can find angle B using the fact that three angles of any triangle add up to 180. Then use law of sines one more time to find side b, or alternatively you can use law of cosines
perl
  • perl
Your welcome :)

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