anonymous
  • anonymous
please help me
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
@perl is familier with it! :-)
tkhunny
  • tkhunny
Very bad question. FAR too subjective. Measure the radial width of the crust vs. the total radius.

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More answers

anonymous
  • anonymous
@perl knows this
perl
  • perl
what is the radius of this pizza, or the diameter
anonymous
  • anonymous
it is 16 inches diameter
anonymous
  • anonymous
large
anonymous
  • anonymous
medium is 12 inches diameter
anonymous
  • anonymous
ya
perl
  • perl
and we need to cut off the top
anonymous
  • anonymous
yup
perl
  • perl
we can make a crude approximation we have an isosceles triangle
anonymous
  • anonymous
ok
perl
  • perl
Area of crust cut off = total area of sector - area of isosceles triangle
perl
  • perl
Area of sector = 1/6 * π r^2 , since we have 6 slices
perl
  • perl
Area of isosceles triangle, this is going to be an equilateral triangle , since the vertex angle is 360/6 = 60 , and the base angles are congruent
perl
  • perl
|dw:1432760771917:dw|
perl
  • perl
you can pick any of the 6 triangles, i just chose that one
anonymous
  • anonymous
ok
perl
  • perl
|dw:1432760838050:dw|
anonymous
  • anonymous
what is the radius?
perl
  • perl
|dw:1432760851340:dw|
perl
  • perl
radius = diameter / 2 = 8
perl
  • perl
https://www.google.com/search?q=area+of+equilateral+triangle&ie=utf-8&oe=utf-8
anonymous
  • anonymous
so the diameter is 16
perl
  • perl
sorry, diameter is twice the radius
perl
  • perl
radius is half the diameter
anonymous
  • anonymous
the area of crust cut off is 26.48.
anonymous
  • anonymous
AM i right
perl
  • perl
nope
anonymous
  • anonymous
Area of crust cut off = total area of sector - area of isosceles triangle A= 1/6*pi(8)^2 - 60
perl
  • perl
whats the formula for the area of an equilateral triangle with side `a` https://www.google.com/search?q=area+of+equilateral+triangle&ie=utf-8&oe=utf-8
anonymous
  • anonymous
27.71
perl
  • perl
A= 1/6*pi(8)^2 - √(3)/ 4 (8)^2
perl
  • perl
yes thats correct
anonymous
  • anonymous
ok I got it
anonymous
  • anonymous
the area of the segment cut off is 5.8
anonymous
  • anonymous
Am i right?
perl
  • perl
yes, but note that this an approximation, since a pizza crust can sometimes be thick We solved the 'ideal' problem
anonymous
  • anonymous
ok thanks :-)
perl
  • perl
this is what we found exactly http://prntscr.com/7a5bjm
perl
  • perl
if we cut it that way
perl
  • perl
so that cut approximates removing the crust
anonymous
  • anonymous
To find the isosceles, why did u divide 360/6
anonymous
  • anonymous
Since the triangle is 180
perl
  • perl
|dw:1432761628546:dw|
perl
  • perl
we have 6 angles, that add up to 360 degrees (in the center)
anonymous
  • anonymous
ohh
perl
  • perl
so thats how you get the vertex angle of a single triangle. then the base angles, you can use the fact that the triangle is isosceles (since the sides are the radius)
anonymous
  • anonymous
if the sides have the radius then it is isosceles
perl
  • perl
yes because all the radii are congruent
anonymous
  • anonymous
why are we using the equilateral triangle formula, why can't we use isosceles
anonymous
  • anonymous
ohh I got it. 60 is common
perl
  • perl
|dw:1432761994892:dw|
anonymous
  • anonymous
yup :-)
perl
  • perl
this isosceles triangle is a special case, its also equilateral
anonymous
  • anonymous
thanks i got
anonymous
  • anonymous
you should actually get infinite medals for this help
anonymous
  • anonymous
it is really understandable
perl
  • perl
|dw:1432762135339:dw|
anonymous
  • anonymous
ok
perl
  • perl
|dw:1432762254726:dw|
perl
  • perl
the base angles of an isosecles triangle are congruent. Therefore we have 60 + x + x = 180 60 + 2x = 180 2x = 120 x = 120/6 = 60 Now you know its an equilateral triangle , since all the angles are congruent
perl
  • perl
|dw:1432762385401:dw|
anonymous
  • anonymous
ok
anonymous
  • anonymous
thanks
anonymous
  • anonymous
I only need 5.8 answer. But, thanks for the work and made me understandable
anonymous
  • anonymous
I am fully confident now
perl
  • perl
:)

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