please help me

- anonymous

please help me

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- chestercat

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- anonymous

##### 1 Attachment

- anonymous

@perl is familier with it! :-)

- tkhunny

Very bad question. FAR too subjective. Measure the radial width of the crust vs. the total radius.

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## More answers

- anonymous

@perl knows this

- perl

what is the radius of this pizza, or the diameter

- anonymous

it is 16 inches diameter

- anonymous

large

- anonymous

medium is 12 inches diameter

- anonymous

ya

- perl

and we need to cut off the top

- anonymous

yup

- perl

we can make a crude approximation
we have an isosceles triangle

- anonymous

ok

- perl

Area of crust cut off = total area of sector - area of isosceles triangle

- perl

Area of sector = 1/6 * π r^2 , since we have 6 slices

- perl

Area of isosceles triangle, this is going to be an equilateral triangle , since the vertex angle is 360/6 = 60 , and the base angles are congruent

- perl

|dw:1432760771917:dw|

- perl

you can pick any of the 6 triangles, i just chose that one

- anonymous

ok

- perl

|dw:1432760838050:dw|

- anonymous

what is the radius?

- perl

|dw:1432760851340:dw|

- perl

radius = diameter / 2 = 8

- perl

https://www.google.com/search?q=area+of+equilateral+triangle&ie=utf-8&oe=utf-8

- anonymous

so the diameter is 16

- perl

sorry, diameter is twice the radius

- perl

radius is half the diameter

- anonymous

the area of crust cut off is 26.48.

- anonymous

AM i right

- perl

nope

- anonymous

Area of crust cut off = total area of sector - area of isosceles triangle
A= 1/6*pi(8)^2 - 60

- perl

whats the formula for the area of an equilateral triangle with side `a`
https://www.google.com/search?q=area+of+equilateral+triangle&ie=utf-8&oe=utf-8

- anonymous

27.71

- perl

A= 1/6*pi(8)^2 - √(3)/ 4 (8)^2

- perl

yes thats correct

- anonymous

ok I got it

- anonymous

the area of the segment cut off is 5.8

- anonymous

Am i right?

- perl

yes, but note that this an approximation, since a pizza crust can sometimes be thick
We solved the 'ideal' problem

- anonymous

ok thanks :-)

- perl

this is what we found exactly http://prntscr.com/7a5bjm

- perl

if we cut it that way

- perl

so that cut approximates removing the crust

- anonymous

To find the isosceles, why did u divide 360/6

- anonymous

Since the triangle is 180

- perl

|dw:1432761628546:dw|

- perl

we have 6 angles, that add up to 360 degrees (in the center)

- anonymous

ohh

- perl

so thats how you get the vertex angle of a single triangle.
then the base angles, you can use the fact that the triangle is isosceles (since the sides are the radius)

- anonymous

if the sides have the radius then it is isosceles

- perl

yes because all the radii are congruent

- anonymous

why are we using the equilateral triangle formula, why can't we use isosceles

- anonymous

ohh I got it. 60 is common

- perl

|dw:1432761994892:dw|

- anonymous

yup :-)

- perl

this isosceles triangle is a special case, its also equilateral

- anonymous

thanks i got

- anonymous

you should actually get infinite medals for this help

- anonymous

it is really understandable

- perl

|dw:1432762135339:dw|

- anonymous

ok

- perl

|dw:1432762254726:dw|

- perl

the base angles of an isosecles triangle are congruent.
Therefore we have
60 + x + x = 180
60 + 2x = 180
2x = 120
x = 120/6 = 60
Now you know its an equilateral triangle , since all the angles are congruent

- perl

|dw:1432762385401:dw|

- anonymous

ok

- anonymous

thanks

- anonymous

I only need 5.8 answer. But, thanks for the work and made me understandable

- anonymous

I am fully confident now

- perl

:)

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