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anonymous

  • one year ago

PLEASE HELP WITH LOGs IF loga5=2.32 and loga3=1.59, find loga45

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  1. MrNood
    • one year ago
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    so - note that 45 = 9*5 you have loga 5 and oyu have log a 3 what is the relationship betweem 3 and 9?

  2. anonymous
    • one year ago
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    im not sure

  3. MrNood
    • one year ago
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    2^2 = 4 3^2 = ?

  4. anonymous
    • one year ago
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    9

  5. MrNood
    • one year ago
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    SO 9 = 3^2 So if loga3 = 1.59 what is loga 3^2

  6. anonymous
    • one year ago
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    would it be 3

  7. MrNood
    • one year ago
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    no this is the key point of th equestion you must be studying logs and their properties so see if you can find a way of simplifying \[\log _{a} x ^{n}\]

  8. anonymous
    • one year ago
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    well that would be n times loga(x)

  9. MrNood
    • one year ago
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    good - you have solved the question! so what is \[\log _{a }3^{^{2}}\]

  10. anonymous
    • one year ago
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    2 times loga(3)

  11. anonymous
    • one year ago
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    loga(5*3)

  12. MrNood
    • one year ago
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    no - you want to find loga(5 * 3^2)

  13. anonymous
    • one year ago
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    i mean 5*9

  14. anonymous
    • one year ago
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    so loga(5)+loga(9)

  15. MrNood
    • one year ago
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    you got it and you have both those numbers..... add em up!

  16. anonymous
    • one year ago
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    but the answer key says 5.50 is that wrong?

  17. MrNood
    • one year ago
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    no you wrote just now what log 3^2 is (it is in YOUR post above... what is log 9? what is log 5 add tehm together

  18. anonymous
    • one year ago
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    i got 2?

  19. MrNood
    • one year ago
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    YOU wrote above "well that would be n times loga(x) so what is log 9 ( it is the same as log 3^2)

  20. anonymous
    • one year ago
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    oh so 2 loga (3)

  21. MrNood
    • one year ago
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    yes - you already wrote that so now oyu can work out loga(5)+loga(9)

  22. anonymous
    • one year ago
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    but im typing that into my calculator and getting 2?

  23. MrNood
    • one year ago
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    you don't need a calculator you are given the numbers in the question what is loga 3? what is 2 loga 3? what is loga 5? soooo - what I slog a 45 you have DONE all the work - you just need to put the steps together you are using the calculator wrong - but that doesn't matter now - you don't need the calculator

  24. MrNood
    • one year ago
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    anyhow - you can't use calc because you don't know what a is

  25. anonymous
    • one year ago
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    oh ok i forgot about the numbers so i got 5.5 with the number

  26. anonymous
    • one year ago
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    thank you so much!

  27. MrNood
    • one year ago
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    np

  28. anonymous
    • one year ago
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    if it's not too much to ask, could you also help me with this last one? i have to condense \[\log_{4} 128-1\]

  29. MrNood
    • one year ago
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    OK it would be good if this was log 4 x - log 4 y Can you make it look like that?

  30. anonymous
    • one year ago
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    i dont think we learned that

  31. MrNood
    • one year ago
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    so if it was to look like I said tehn we can see that log4 y = 1 what is y? (think about the meaning of what loga really means) (I think you seem to have the skills to do this...)

  32. anonymous
    • one year ago
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    do you mean y=128 or do you want it in exponential form?

  33. MrNood
    • one year ago
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    no - it is not y=128 what is \[\log_{10} 10\] or \[\log_{e} e\]

  34. anonymous
    • one year ago
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    1?

  35. MrNood
    • one year ago
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    yes so logn n =1 for any n so we can write your original equation as log4 128 - log 4 4 can oyu simplify from there?

  36. anonymous
    • one year ago
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    i got 32 but the answer is 5/2

  37. anonymous
    • one year ago
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    because i did log4 128/4

  38. MrNood
    • one year ago
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    ok - you have not quite done the simplification properly what is log a - log b?

  39. anonymous
    • one year ago
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    would you use the change of base property

  40. MrNood
    • one year ago
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    no - sorry - I was being slack in notation - forget that you are nearly there go back to log4 128 - log 4 4 can oyu simplify from there? And try again - you made a small mistake....

  41. anonymous
    • one year ago
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    log4 (128/4)?

  42. MrNood
    • one year ago
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    yes

  43. anonymous
    • one year ago
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    oh i got i! you convert it to exponential so you get 5/2

  44. anonymous
    • one year ago
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    thanks so much!

  45. MrNood
    • one year ago
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    not sure I follow that

  46. MrNood
    • one year ago
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    log4 (128/4) = log4 (32) which IS 5/2 but I need to see how you got there....

  47. anonymous
    • one year ago
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    i got 4^x =32 and then you do (2^2)^x=(2^5) and 2x=5 is 5/2

  48. MrNood
    • one year ago
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    OK - I see 32 = 2^5 so 4^5 /4^2

  49. anonymous
    • one year ago
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    yeah

  50. MrNood
    • one year ago
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    well done

  51. anonymous
    • one year ago
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    thanks so much!!

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