Solve 3(x + 2) > x. {x | x < -1} {x | x > -1} {x | x < -3} {x | x > -3}

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Solve 3(x + 2) > x. {x | x < -1} {x | x > -1} {x | x < -3} {x | x > -3}

Mathematics
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Well, first distribute the left side to get rid of the parenthesis
i dont know how to distribute
Let me show you:

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\[3\left( x+2 \right)>x\] 3x+6>x 3x+6-x>x-x 2x+6>0 subtract 6 from both sides and then divide by 2
|dw:1432763780277:dw|
do i divide both sides by 6 now?
Hmm, close, try *subtracting* both sides by 6.
|dw:1432764029685:dw|
Now what do you think you should do?
divide by 3?
Yes! On both sides.
|dw:1432764187034:dw|
Now what do you think you should do?
subtract 2?
Remember: We need to bring the x's onto one side because we are trying to isolate the x variable in order to find x.
Try subtracting the x on the right on both sides
does that give me >-2?
No, try again
|dw:1432764486779:dw|
so i have x>-2+x
and if i remove x from both sides
Yes, but I believe I did something wrong. Let me solve this on my own. I apologize
I got x > -3. Let me show you.
tep 1 : Simplify 3•(x+2) - x Pulling out like terms : 1.1 Pull out like factors : 2x + 6 = 2 • (x + 3) Equation at the end of step 1 : 2 • (x + 3) > 0 Step 2 : Solve 2•(x+3) > 0 Divide both sides of the ineqaulity by 2 x+3 > 0
Then subtract both sides by 3. =
|dw:1432764749555:dw|
that really helped. thank you for explaining. i understand
Awesome! Try tipping with a medal + fan whenever someone else helps you out. It truly motivates them to help others, too.

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