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omarbirjas

  • one year ago

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  1. Nnesha
    • one year ago
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    |dw:1432764356616:dw| what is angle C all triangles add up to 180 degree first find angle C

  2. omarbirjas
    • one year ago
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    107

  3. Nnesha
    • one year ago
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    nvm you don't have to

  4. Nnesha
    • one year ago
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    \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\] which one you should apply ?

  5. omarbirjas
    • one year ago
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    umm....idk since there is no hypotenues

  6. Nnesha
    • one year ago
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    to find AB you should know one angle and one side

  7. Nnesha
    • one year ago
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    ohhh i got your point lol

  8. Nnesha
    • one year ago
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    familiar with law of cosines and law of sines ?

  9. omarbirjas
    • one year ago
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    uggghhhh i hate that stuff....

  10. omarbirjas
    • one year ago
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    never really understood it....

  11. Nnesha
    • one year ago
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    bec given : two angle and one side so you have to use law of sines \[\huge\rm \frac{ \sin A }{ a } = \frac{ \sin B }{ b }=\frac{ \sin C }{ c }\]

  12. Nnesha
    • one year ago
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    |dw:1432765654408:dw| \[\huge\rm \frac{ \sin B }{ b } = \frac{ \sin C }{ c}\] plug in value solve for c

  13. Nnesha
    • one year ago
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    yep right angle C is 107

  14. omarbirjas
    • one year ago
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    Yea so \[\frac{ \sin 41 }{ a}=\frac{ \sin 32 }{ 9}\]

  15. Nnesha
    • one year ago
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    you have to find AB so sin C over c

  16. omarbirjas
    • one year ago
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    sin 32/9 = sin 107/c

  17. Nnesha
    • one year ago
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    yep

  18. omarbirjas
    • one year ago
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    16.24

  19. Nnesha
    • one year ago
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    ye

  20. omarbirjas
    • one year ago
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    thank you berry machs

  21. Nnesha
    • one year ago
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    huh ? anyways np :-)

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