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anonymous
 one year ago
Factor: x2 + 11x + 28
A. (x + 7)(x + 4)
B. (x + 7)(x  4)
C. (x + 8)(x + 3)
D. (x + 14)(x + 2)
anonymous
 one year ago
Factor: x2 + 11x + 28 A. (x + 7)(x + 4) B. (x + 7)(x  4) C. (x + 8)(x + 3) D. (x + 14)(x + 2)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sure.. give me two mins

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so first off, I need to know your understanding of factoring trinomials before I give you the straight out answer. (I give explanations too but I just need to know you understand this, too)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i didnt get it that much @Aureyliant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Trying to factor by splitting the middle term 2.1 Factoring x2+11x+28 The first term is, x2 its coefficient is 1 . The middle term is, +11x its coefficient is 11 . The last term, "the constant", is +28 Step1 : Multiply the coefficient of the first term by the constant 1 • 28 = 28 Step2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is 11 . 28 + 1 = 29 14 + 2 = 16 7 + 4 = 11 4 + 7 = 11 2 + 14 = 16 1 + 28 = 29 1 + 28 = 29 2 + 14 = 16 4 + 7 = 11 That's it Step3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 4 and 7 x2 + 4x + 7x + 28 Step4 : Add up the first 2 terms, pulling out like factors : x • (x+4) Add up the last 2 terms, pulling out common factors : 7 • (x+4) Step5 : Add up the four terms of step 4 : (x+7) • (x+4) Which is the desired factorization Final result : (x + 7) • (x + 4)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Read this and ask me any Q's or tell me anywhere you're confused.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait did you mean 2x or x+2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i get it now @Aureyliant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0AWESOME!! I love "hearing" that from people I help.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Need anymore help? Just tag me :)
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