anonymous
  • anonymous
log(3x+5)-log(x-5)=log(8)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
i got it so log(3x+5/x-5)=log8 and dont know where to go from there
Nnesha
  • Nnesha
hint: \[\huge\rm log_b x = \log_b y\] \[\huge\rm\cancel { log_b} x = \cancel{\log_b} y\] x=y
anonymous
  • anonymous
so 3x-5/x-5=8

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More answers

Nnesha
  • Nnesha
yep now simple algebra
anonymous
  • anonymous
i got -20 but the answer is 9
Nnesha
  • Nnesha
how did you get -20?
anonymous
  • anonymous
i cross multiplied
anonymous
  • anonymous
so 8x-40=3x+5
Nnesha
  • Nnesha
solve for x
anonymous
  • anonymous
i got -20
Nnesha
  • Nnesha
show ur work
anonymous
  • anonymous
oh i found my mistake thank you!
Nnesha
  • Nnesha
r u sure ? u got it ?
anonymous
  • anonymous
yep! can i ask you one more though?
Nnesha
  • Nnesha
alright
anonymous
  • anonymous
log8+3logx=3 which i know is log8+logx^3=3 but what do you do if theres no log on the other side?
Nnesha
  • Nnesha
apply log properties which one you should apply ?
anonymous
  • anonymous
change of base?
Nnesha
  • Nnesha
yeah or convert log to exponential form just like we did before
Nnesha
  • Nnesha
nope there is a variable so you can't use change of base formula
anonymous
  • anonymous
how would you do that though because isnt it 8x^3=3
Nnesha
  • Nnesha
log (8x^3) = 3
Nnesha
  • Nnesha
\[\log = \log_{10}\]
anonymous
  • anonymous
but idk how you would make that exponential
Nnesha
  • Nnesha
|dw:1432768266869:dw|
anonymous
  • anonymous
but theres no base
Nnesha
  • Nnesha
there is i just posted that
Nnesha
  • Nnesha
\[\log = \log_{10}\]
anonymous
  • anonymous
oh ok so then i get 10 though and the answe r is 5
Nnesha
  • Nnesha
xo x = 5 ?
anonymous
  • anonymous
10^3=x^3 which is 10
anonymous
  • anonymous
oh i forgot the 8
anonymous
  • anonymous
oh ok so x=5 got it thanks
Nnesha
  • Nnesha
yep

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