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Z4K4R1Y4
 one year ago
Show that x=Be^(µt) is a solution of mx ̈+kx=0
Z4K4R1Y4
 one year ago
Show that x=Be^(µt) is a solution of mx ̈+kx=0

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0it's not. differentiate it.

Z4K4R1Y4
 one year ago
Best ResponseYou've already chosen the best response.0I know i differentiated it and didn't get the right answer.

Z4K4R1Y4
 one year ago
Best ResponseYou've already chosen the best response.0I've been given some more information: B=Ae^jϕ

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0better. but have you differentiated that?? it's suddenly become more complicated!

Z4K4R1Y4
 one year ago
Best ResponseYou've already chosen the best response.0I'm afraid to try, but i'll give it a go.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0lol! \[x=B e^{µ t} \ : \ B=A e^{jϕ} \ \ : \ µ=α+j ω \\ x=A e^{jϕ} e^{(α+j ω) t}\] \[x = A e^{α t+j ( ω t + \phi ) }\] looks interesting!!
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