anonymous
  • anonymous
Square RSTU is shown below with a line AB drawn through its center. If the square is dilated using a scale factor of one over four and a line is drawn through the center of the new dilated figure, what relationship will that line have with line AB in the drawing below?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
anonymous
  • anonymous
@johnweldon1993 can u plz help me
johnweldon1993
  • johnweldon1993
Okay, so we have a square with a line through the middle right? |dw:1432769367326:dw|

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johnweldon1993
  • johnweldon1993
And then that same square is dilated by a factor of \(\large \dfrac{1}{4}\) So that would be multiplying every coordinate by \(\large \dfrac{1}{4}\) I have labeled the coordinates for this reason :)
johnweldon1993
  • johnweldon1993
So for example...the coordinate (1,1) multiplied by 1/4 would be \(\large (\frac{1}{4}, \frac{1}{4})\) make sense so far?
anonymous
  • anonymous
yes sir (:
johnweldon1993
  • johnweldon1993
Good :) so the new square we will have is *gonna try and draw it in the previous one to show this better* |dw:1432769675980:dw|
johnweldon1993
  • johnweldon1993
SOOOOOO if we draw a line through the center of the new square what do we see? |dw:1432769815446:dw|
anonymous
  • anonymous
we see that AB relationship whould based on x and y ? i think
johnweldon1993
  • johnweldon1993
Well I would just say that they are the same line...since lines are never ending I dont believe we need to subject it to an 'xy' relationship For a square, no matter what factor you scale it by...the line going straight through the original center will also always go through the "new" center as the same line
anonymous
  • anonymous
oh ok so what relationship will that line have with line AB in the drawing below?
johnweldon1993
  • johnweldon1993
They are the same line...that is the relationship :D
anonymous
  • anonymous
oh ok thank you so much (:
johnweldon1993
  • johnweldon1993
Of course :)

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