anonymous
  • anonymous
y = (x+3)(x-5) uadratic equation
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Have you heard of the FOIL method?
anonymous
  • anonymous
i really don't have the hang of it
anonymous
  • anonymous
Okay, no problem. It's super simple! Give me a sec while i draw this out okay?

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anonymous
  • anonymous
okay thank you
anonymous
  • anonymous
|dw:1432769861044:dw|
anonymous
  • anonymous
You multiply all those out. Add everything together that has matching variables and that will be your quadratic equation.
anonymous
  • anonymous
Sorry my handwriting is awful. It's hard with a mouse and i have shaky hands.
anonymous
  • anonymous
thank you so much
anonymous
  • anonymous
Post your answer once you get it and i'll check to make sure it's correct okay?
anonymous
  • anonymous
is it -3,5?
anonymous
  • anonymous
Nope, not quite. Here let me show you further.\[x \times x + 3 \times x - 5 \times x - 3 \times 5\]
anonymous
  • anonymous
does that make more sense to what my drawing shows?
brunsonni
  • brunsonni
to further elaborate on what agentc0re is saying, if you have (x+3)(x-5), you take the x from (x+3), and distribute it to the x, and -5, from the second expression, which is where agentc0re got x*x+x*-5. Then you use the 3, and do the same, which gives you 3*x+3*-5. once you have the two halves, you combine them, so, x*x+x*-5+3*x+3*-5. Now you multiply. x*x is x^2, x*-5 is -5x, 3*x is 3x, and 3*-5 is -15. Now you put those together, giving you x^2-5x+3x-15. Lastly, you combine like terms, giving you a final answer of x^2-2x-15.

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