At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
Have you heard of the FOIL method?
i really don't have the hang of it
Okay, no problem. It's super simple! Give me a sec while i draw this out okay?
okay thank you
You multiply all those out. Add everything together that has matching variables and that will be your quadratic equation.
Sorry my handwriting is awful. It's hard with a mouse and i have shaky hands.
thank you so much
Post your answer once you get it and i'll check to make sure it's correct okay?
is it -3,5?
Nope, not quite. Here let me show you further.\[x \times x + 3 \times x - 5 \times x - 3 \times 5\]
does that make more sense to what my drawing shows?
to further elaborate on what agentc0re is saying, if you have (x+3)(x-5), you take the x from (x+3), and distribute it to the x, and -5, from the second expression, which is where agentc0re got x*x+x*-5. Then you use the 3, and do the same, which gives you 3*x+3*-5. once you have the two halves, you combine them, so, x*x+x*-5+3*x+3*-5. Now you multiply. x*x is x^2, x*-5 is -5x, 3*x is 3x, and 3*-5 is -15. Now you put those together, giving you x^2-5x+3x-15. Lastly, you combine like terms, giving you a final answer of x^2-2x-15.