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anonymous

  • one year ago

y = (x+3)(x-5) uadratic equation

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  1. anonymous
    • one year ago
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    Have you heard of the FOIL method?

  2. anonymous
    • one year ago
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    i really don't have the hang of it

  3. anonymous
    • one year ago
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    Okay, no problem. It's super simple! Give me a sec while i draw this out okay?

  4. anonymous
    • one year ago
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    okay thank you

  5. anonymous
    • one year ago
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    |dw:1432769861044:dw|

  6. anonymous
    • one year ago
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    You multiply all those out. Add everything together that has matching variables and that will be your quadratic equation.

  7. anonymous
    • one year ago
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    Sorry my handwriting is awful. It's hard with a mouse and i have shaky hands.

  8. anonymous
    • one year ago
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    thank you so much

  9. anonymous
    • one year ago
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    Post your answer once you get it and i'll check to make sure it's correct okay?

  10. anonymous
    • one year ago
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    is it -3,5?

  11. anonymous
    • one year ago
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    Nope, not quite. Here let me show you further.\[x \times x + 3 \times x - 5 \times x - 3 \times 5\]

  12. anonymous
    • one year ago
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    does that make more sense to what my drawing shows?

  13. brunsonni
    • one year ago
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    to further elaborate on what agentc0re is saying, if you have (x+3)(x-5), you take the x from (x+3), and distribute it to the x, and -5, from the second expression, which is where agentc0re got x*x+x*-5. Then you use the 3, and do the same, which gives you 3*x+3*-5. once you have the two halves, you combine them, so, x*x+x*-5+3*x+3*-5. Now you multiply. x*x is x^2, x*-5 is -5x, 3*x is 3x, and 3*-5 is -15. Now you put those together, giving you x^2-5x+3x-15. Lastly, you combine like terms, giving you a final answer of x^2-2x-15.

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