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dtan5457

  • one year ago

If 4 fair dice are rolled, what is the probability that at least 2 are fives?

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  1. kropot72
    • one year ago
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    \[\large P(2\ fives)=4C2 \times (\frac{1}{6})^{2} \times(\frac{5}{6})^{2}\] Then we need to use the binomial distribution again to find P(3 fives) and P(4 fives) and add the three values of probability together.

  2. kropot72
    • one year ago
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