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anonymous
 one year ago
Write an equation of a line parallel to y = 2 over 3x −5 in slopeintercept form that passes through the point (−6, −1).
y= 2 over 3x + 3
y= 2 over 3x − 6
y= −3x − 1
y= 3x + 6
anonymous
 one year ago
Write an equation of a line parallel to y = 2 over 3x −5 in slopeintercept form that passes through the point (−6, −1). y= 2 over 3x + 3 y= 2 over 3x − 6 y= −3x − 1 y= 3x + 6

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0parallel lines have the same slope. what is the slope of the given line?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge y =\color{red}{\frac{2}{3}}x5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what's the slope?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0hint: it is big and red !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we know our answer will have a slope of 2/3, and go through the point (6, 1). we can plug that information into pointslope form, which is y  y1 = m(x  x1) where y1 is the ycoordinate of the point, x1 is the xcoordinate of the same point, and m is slope what do you get once you plug that in?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im Confused Of How To Plug It In

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0"plugging in" is just another word for substitute

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so for m, we'll "plug in" 2/3. get it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes I Know That But Im Confused Of The Order To Plugging It In.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0our point is (6, 1). y1 is the y part of that point. and x1 is the x part of that point.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0points are in the form of (x,y)...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you there? @jaygamble
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