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- anonymous

State the x- intercept and y- intercept for the graph of each equation. Then graph the equation using x- and y-intercepts
1) 2x + 3y = 12
2) y = -2x -4
I hope someone maybe able to help me so I understand I submitted these two above and I got them wrong so I hope someone maybe able to help me so I understand as I am not sure what I have done wrong. Thanks

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- anonymous

- jamiebookeater

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- AriPotta

to find the x-intercept, substitute 0 for y in the equation and solve for x.
to find the y-intercept, substitute 0 for x in the equation and solve for y.
then to graph, just graph the intercepts on the coordinate plane, and then draw a line through the points

- anonymous

you plug in the y equation into the x one.
2x+3(-2x-4)=12
2x+-6x-12=12
-4x-12=12
-4x=24
x=-6, then plug in -6 into the y equation.
y= -2(-6)-4
y= 12-4
y= 8
you should have (-6,8)

- anonymous

I am confused I got (-6, 4)
and for number two I have (-2. -4)
not sure what I did wrong

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- AriPotta

x-intercept is going to be (x, 0) and y-intercept is going to be (0, y)

- AriPotta

do what i said, and you should be all set

- anonymous

I think I understand a little better Thanks

- AriPotta

1) 2x + 3y = 12
to find x-intercept:
2x + 3(0) = 12
solve for x
to find y-intercept:
2(0) + 3y = 12
solve for y

- anonymous

Thanks

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