Please help me simplify a quadratic equation. (x^2 + 2x +1) + (y^2 + 4y +4) = 25

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Please help me simplify a quadratic equation. (x^2 + 2x +1) + (y^2 + 4y +4) = 25

Mathematics
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HI!!
you seem to have two variables there, but each term in parentheses is a perfect square
you can rewrite it as \[(x+1)^2+(y+2)^2=25\] so it is the equation for a circle

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Other answers:

Yes, that is what we were supposed to do. It is to find the midpoint of a circle along with the radius
it is not a "quadratic equation" nor can you "simplify" it, but you can write it in the standard from for a circle
Terribly sorry, my internet likes to go out on me
How would I write it in standard form ?
it is not the internet, is is OS today
Oh okay so how would I write it in standard form like you said?
i did already
Oh okay, I see
\[x^2+2x+1=(x+1)^2\] and \[y^2+4y+4=(y+2)^2\]
you get \[(x+1)^2+(y+2)^2=25\] and from that you can read off the center and the radius
you got that or no?
I used an online calculator to try this and ended up with "The center is (-1,-2) and the radius is 5." Would this be correct? Or would my points have to be positive
And yes, I understand now
that is correct form is \[(x-h)^2+(y-k)^2=r^2\]
Okay, Thank you for all of your help :)

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