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anonymous

  • one year ago

Please help me simplify a quadratic equation. (x^2 + 2x +1) + (y^2 + 4y +4) = 25

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    you seem to have two variables there, but each term in parentheses is a perfect square

  3. misty1212
    • one year ago
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    you can rewrite it as \[(x+1)^2+(y+2)^2=25\] so it is the equation for a circle

  4. anonymous
    • one year ago
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    Yes, that is what we were supposed to do. It is to find the midpoint of a circle along with the radius

  5. misty1212
    • one year ago
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    it is not a "quadratic equation" nor can you "simplify" it, but you can write it in the standard from for a circle

  6. anonymous
    • one year ago
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    Terribly sorry, my internet likes to go out on me

  7. anonymous
    • one year ago
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    How would I write it in standard form ?

  8. misty1212
    • one year ago
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    it is not the internet, is is OS today

  9. anonymous
    • one year ago
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    Oh okay so how would I write it in standard form like you said?

  10. misty1212
    • one year ago
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    i did already

  11. anonymous
    • one year ago
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    Oh okay, I see

  12. misty1212
    • one year ago
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    \[x^2+2x+1=(x+1)^2\] and \[y^2+4y+4=(y+2)^2\]

  13. misty1212
    • one year ago
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    you get \[(x+1)^2+(y+2)^2=25\] and from that you can read off the center and the radius

  14. misty1212
    • one year ago
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    you got that or no?

  15. anonymous
    • one year ago
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    I used an online calculator to try this and ended up with "The center is (-1,-2) and the radius is 5." Would this be correct? Or would my points have to be positive

  16. anonymous
    • one year ago
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    And yes, I understand now

  17. misty1212
    • one year ago
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    that is correct form is \[(x-h)^2+(y-k)^2=r^2\]

  18. anonymous
    • one year ago
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    Okay, Thank you for all of your help :)

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