## anonymous one year ago A cube is cut perpendicular to and diagonally across the base, as shown below.

1. anonymous

2. anonymous

What is the ratio of the area of the shaded cross-section to the area of one of the square faces of the cube? 1 : 1 2√:1 3√:1 2 : 1

3. anonymous

@iloveyouboo

4. anonymous

@dan815

5. anonymous

Help Me Boo

6. anonymous

lol

7. anonymous

@LyricalDevonne He Better Help Me

8. anonymous

i got u gurl @ly

9. anonymous

@LyricalDevonne

10. anonymous

guess he is to busy for us ...

11. anonymous

He Better Get His Giant Self In Here And Help Me

12. zepdrix

lol XD

13. zepdrix

hmm thinking -_-

14. anonymous

i jus dont wanna give u the wrong answer

15. zepdrix

|dw:1432784345118:dw|So if it's cut across the diagonal like this,

16. zepdrix

let's ignore the height for a sec, look at the base, we can find the length of the hypotenuse by using our pythagorean theorem, ya? :)

17. anonymous

@LyricalDevonne U Better Help Me

18. anonymous

lol he's doing it for youCx

19. anonymous

do you guys share an internet boyfriend?

20. anonymous

NOOOOOOOOOOOOOO

21. anonymous

ummmm, i have a gf...

22. anonymous

well zepdrix gave you the answer, just plug it in and solve

23. anonymous

Ohhh U Played My Lifee

24. anonymous

?

25. anonymous

Im Bout To Use That Button

26. zepdrix

So we've got uhhh,, $$\Large\rm a^2+a^2=c^2$$ where c is the hypotenuse, ya? Solve for that length c.

27. zepdrix

|dw:1432784993245:dw|The area of the diagonal wall that was cut is given by width times the height, so that hypotenuse length times the height a. $$\Large\rm c\cdot a$$ And the area of any face is going to be $$\Large\rm a\cdot a$$ So the ration is ca:aa or to simplify things lets call the side lengths 1 as the gal was suggesting earlier :) c:1 So find that hypotenuse length!