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zepdrix

  • one year ago

Studayyyyyyy Taymeeeeeee!

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  1. zepdrix
    • one year ago
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    |dw:1432784644165:dw| @Compassionate come nao!! +_+

  2. zepdrix
    • one year ago
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    Circle `b` has area 121 times greater than area if `a` \[\Large\rm A_b=121A_a\]

  3. zepdrix
    • one year ago
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    Area is pi(r)^2, ya?

  4. zepdrix
    • one year ago
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    \[\Large\rm A_b=121A_a\]So I'll plug in our formula for area,\[\Large\rm \pi r_b^2=121(\pi r_a^2)\]They told us the radius of circle b is 44,\[\Large\rm \pi (44)^2=121(\pi r_a^2)\]Solve for r! :)

  5. Compassionate
    • one year ago
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    OS just loaded for me. Sigh. Okay, wait so we did the formula for a circle and plugged in the parts, but what is the pi(44)^2 at the end?

  6. zepdrix
    • one year ago
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    I hope the r's weren't too confusing. I was calling the radius of circle b, \(\Large\rm r_b\) and the radius of circle a, \(\Large\rm r_a\). So we have our area relationships,\[\Large\rm \color{orangered}{A_b}=121\color{royalblue}{A_a}\]I'm plugging in the formula for area of a circle on each side, with a's radius on the right, b's radius on the left side,\[\Large\rm \color{orangered}{\pi (r_b)^2}=121\cdot\color{royalblue}{\pi(r_a)^2}\]And then I'm plugging in the value of the radius of circle b, they told us the radius of circle b is 44,\[\Large\rm \color{orangered}{\pi (44)^2}=121\cdot\color{royalblue}{\pi(r_a)^2}\]

  7. zepdrix
    • one year ago
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    The pi(44)^2 is `pi` times `radius of circle b squared`, area of circle b.

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