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Curry

  • one year ago

Help with physics question.

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  1. Curry
    • one year ago
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  2. Curry
    • one year ago
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    @nincompoop Please ? I posted twice, I didn't get any help...

  3. Curry
    • one year ago
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    @myininaya

  4. Curry
    • one year ago
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    @Preetha @dan815

  5. Curry
    • one year ago
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    @Zarkon

  6. anonymous
    • one year ago
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    Olmost got it

  7. Curry
    • one year ago
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    the answer is 2/9. but I don't understand the work behind it. they did (1/3m)(Mx1 + m(x1+ l/4) + m(x1+l/4+l/2). with x1 being the amount of the book ON the table.

  8. Curry
    • one year ago
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    @Hero

  9. anonymous
    • one year ago
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    sorry cant help

  10. anonymous
    • one year ago
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    1/3m( mx1+m(x1+1/4)+m(x1+1/4+1/2) x1=-1/3, 1/2-1/3= 1/6 1/6 bottom book can over hang

  11. Curry
    • one year ago
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    why is the second value x1 + 1/4 though?

  12. Curry
    • one year ago
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    I would imagine it'd be x1- l/4. right? cause that's the part of the book that's on the table?

  13. anonymous
    • one year ago
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    Center of mass of each book at its center

  14. Curry
    • one year ago
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    mhmm. and then?

  15. anonymous
    • one year ago
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    Because furthest right is the center of mass, then take origin st edge postive to right

  16. Curry
    • one year ago
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    wait, i don't understand what you're saying exactly, sorry! can you please explain it diferently?

  17. anonymous
    • one year ago
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    |dw:1432797245916:dw|

  18. anonymous
    • one year ago
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    Also you pushing from the right side, so we are going with the normal force and not against it

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