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Curry
 one year ago
Help with physics question.
Curry
 one year ago
Help with physics question.

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Curry
 one year ago
Best ResponseYou've already chosen the best response.0@nincompoop Please ? I posted twice, I didn't get any help...

Curry
 one year ago
Best ResponseYou've already chosen the best response.0the answer is 2/9. but I don't understand the work behind it. they did (1/3m)(Mx1 + m(x1+ l/4) + m(x1+l/4+l/2). with x1 being the amount of the book ON the table.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01/3m( mx1+m(x1+1/4)+m(x1+1/4+1/2) x1=1/3, 1/21/3= 1/6 1/6 bottom book can over hang

Curry
 one year ago
Best ResponseYou've already chosen the best response.0why is the second value x1 + 1/4 though?

Curry
 one year ago
Best ResponseYou've already chosen the best response.0I would imagine it'd be x1 l/4. right? cause that's the part of the book that's on the table?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Center of mass of each book at its center

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because furthest right is the center of mass, then take origin st edge postive to right

Curry
 one year ago
Best ResponseYou've already chosen the best response.0wait, i don't understand what you're saying exactly, sorry! can you please explain it diferently?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432797245916:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Also you pushing from the right side, so we are going with the normal force and not against it
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