solve the cubic polynomial,f(x)=6x^3+5x^2-12x+4 and find the relationship between the zeros and coefficients of the polynomail
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the last number 4 has factors \(\pm1\), \(\pm 2\), \(\pm 4\)
the first number 6 has factors \(\pm 1\), \(\pm2\), \(\pm 3\), \(\pm 6\)
hence the factors of 6 will go with the factor of 4 to form the zeros of the polynomial but it is the denominator. I meant |dw:1432874701462:dw|
put \(\pm\) on each of them.
Fortunately, the cubic has at most 3 zeros, hence if we find out 1 of them, the rest is easy.
The logic above is the answer for "Relationship between the zeros and coefficients of the polynomial"
Now is to find the zero.
test -2, you get y =0, hence (x+2) is a factor of the polynomial.
take long division to find other zeros.
Are you allowed to use calculator?
ok, good luck, you have to check one by one among the options I gave you above.