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anonymous

  • one year ago

solve the cubic polynomial,f(x)=6x^3+5x^2-12x+4 and find the relationship between the zeros and coefficients of the polynomail

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  1. anonymous
    • one year ago
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    help me.....................please .i Will give medal

  2. Loser66
    • one year ago
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    still need help?

  3. anonymous
    • one year ago
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    yes

  4. Loser66
    • one year ago
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    the last number 4 has factors \(\pm1\), \(\pm 2\), \(\pm 4\) the first number 6 has factors \(\pm 1\), \(\pm2\), \(\pm 3\), \(\pm 6\) hence the factors of 6 will go with the factor of 4 to form the zeros of the polynomial but it is the denominator. I meant |dw:1432874701462:dw|

  5. Loser66
    • one year ago
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    put \(\pm\) on each of them.

  6. Loser66
    • one year ago
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    Fortunately, the cubic has at most 3 zeros, hence if we find out 1 of them, the rest is easy.

  7. Loser66
    • one year ago
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    The logic above is the answer for "Relationship between the zeros and coefficients of the polynomial" Now is to find the zero.

  8. Loser66
    • one year ago
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    test -2, you get y =0, hence (x+2) is a factor of the polynomial. take long division to find other zeros. Are you allowed to use calculator?

  9. anonymous
    • one year ago
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    no

  10. Loser66
    • one year ago
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    ok, good luck, you have to check one by one among the options I gave you above.

  11. Loser66
    • one year ago
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    |dw:1432875418149:dw|

  12. anonymous
    • one year ago
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    thank u : ) i understand this answer

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