3. On his high school’s football team, Jeffrey makes the extra point made 60% of the time. In a particular game versus the team’s biggest rivals, he had 6 extra point attempts. Assume independence between kicks.
a. Based on his average, what was the probability that all 6 attempts are successful?
b. What is the probability that at least 1 was successful?
c. What is the probability that at least 1 is not successful?

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

- anonymous

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- Vocaloid

a. probability that all six attempts are successful: (0.6)^6, because he is throwing six times and the probability of each success is 0.6
b. to find the probability that at least one was successful, consider the opposite scenario. the probability that all failed is (0.4)^6, because the probability of failure is 0.4 and he is throwing six times.
the probability that at least one was successful = 1 - (0.4)^6
c. using the same reasoning, we conclude that the probability that at least 1 is not successful = 1 - (0.6)^6
tag me if you are still confused

- Vocaloid

@NandagopalPV also, I see you have posted this question 3 times, would you mind closing the other two?

- anonymous

Okay, Sorry about that.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- Vocaloid

no big deal, but do you understand the math?

- anonymous

Yeah, thanks I was a little confused at first but you cleared my doubts. Thanks.

- Vocaloid

No problem, I'm glad I was able to help :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.