anonymous
  • anonymous
3. On his high school’s football team, Jeffrey makes the extra point made 60% of the time. In a particular game versus the team’s biggest rivals, he had 6 extra point attempts. Assume independence between kicks. a. Based on his average, what was the probability that all 6 attempts are successful? b. What is the probability that at least 1 was successful? c. What is the probability that at least 1 is not successful?
Probability
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Vocaloid
  • Vocaloid
a. probability that all six attempts are successful: (0.6)^6, because he is throwing six times and the probability of each success is 0.6 b. to find the probability that at least one was successful, consider the opposite scenario. the probability that all failed is (0.4)^6, because the probability of failure is 0.4 and he is throwing six times. the probability that at least one was successful = 1 - (0.4)^6 c. using the same reasoning, we conclude that the probability that at least 1 is not successful = 1 - (0.6)^6 tag me if you are still confused
Vocaloid
  • Vocaloid
@NandagopalPV also, I see you have posted this question 3 times, would you mind closing the other two?
anonymous
  • anonymous
Okay, Sorry about that.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Vocaloid
  • Vocaloid
no big deal, but do you understand the math?
anonymous
  • anonymous
Yeah, thanks I was a little confused at first but you cleared my doubts. Thanks.
Vocaloid
  • Vocaloid
No problem, I'm glad I was able to help :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.