anonymous
  • anonymous
A fair coin is tossed 4 times in a row. If X is the number of heads counted, which table gives the probability distribution of X?
Mathematics
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chestercat
  • chestercat
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anonymous
  • anonymous
@rational
anonymous
  • anonymous
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rational
  • rational
whats the probability for getting heads on all 4 coins ?

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anonymous
  • anonymous
1/2?
rational
  • rational
how ?
rational
  • rational
may i know why do you think it is 1/2
anonymous
  • anonymous
its a 50/50 chance to land on head.
rational
  • rational
its a 50/50 chance to land head on one coin
rational
  • rational
but when you have four coins, the probability for landing heads on "ALL" four coins need not be 1/2 right
rational
  • rational
the probability is actually 1/2*1/2*1/2*1/2 = 1/16
anonymous
  • anonymous
so what like 1/4?
anonymous
  • anonymous
oh sorry. 4 coins. my bad
rational
  • rational
Yes, another question whats the probability for getting NOT getting heads in any of the four coins ?
anonymous
  • anonymous
1/2 each so total would be another 1/16?
rational
  • rational
Yep! so P(X=0) is 1/16 and P(X=4) is also 1/16
rational
  • rational
Now, whats the probability of getting exactly ONE head ?
rational
  • rational
P(X=1) = ?
anonymous
  • anonymous
I would think 1/2 but i know thats not it
rational
  • rational
one way to get exactly ONE head is : H T T T
rational
  • rational
notice that there are 3 other ways to get exactly ONE head : T H T T T T H T T T T H
rational
  • rational
so the probability for getting exactly ONE head is 4/16 = 1/4
rational
  • rational
see if that makes sense
anonymous
  • anonymous
Yes it does, I see what you mean now. okay.
rational
  • rational
look at the options
anonymous
  • anonymous
A?
rational
  • rational
|dw:1432817476450:dw|
rational
  • rational
Yes! our work so far matches perfectly with option A
anonymous
  • anonymous
Yes thats why I said A, the work matches A and not others

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