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anonymous

  • one year ago

can someone check my answer? What is the least common denominator of the fraction 2 over x plus the fraction x over x plus 1 plus the fraction x plus 1 over 3 x ? 3x + 1 3(x2 + 1) 3(x + 3) 3x(x + 1) < --- my choice

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  1. anonymous
    • one year ago
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    \[\frac{ 2 }{ x } + \frac{ x }{ x + 1 } + \frac{ x + 1 }{ 3x }\]

  2. anonymous
    • one year ago
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    lol x

  3. anonymous
    • one year ago
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    least common denominator not numerator

  4. anonymous
    • one year ago
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    so something that can multiply into all of the bottom =)

  5. anonymous
    • one year ago
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    i think its 3x(x + 1)

  6. anonymous
    • one year ago
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    heres the definition "another term for lowest common denominator".

  7. anonymous
    • one year ago
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    yeah i know what denominator means its just that when i see a variable it confuses me

  8. anonymous
    • one year ago
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    A =)

  9. anonymous
    • one year ago
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    3x x x gives you 3x^2 i believe =)

  10. anonymous
    • one year ago
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    i thought 3x x x = 3x^3 because you have 3 x's

  11. anonymous
    • one year ago
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    so you don't think its D you think its A?

  12. anonymous
    • one year ago
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    ur right =)

  13. anonymous
    • one year ago
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    lol i was confusing myself ... idk how though ...

  14. anonymous
    • one year ago
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    so it's D ?

  15. anonymous
    • one year ago
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    Yeah ...

  16. anonymous
    • one year ago
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    k thnx

  17. anonymous
    • one year ago
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    yeah sorry i was thinking of some other stupid formula ...

  18. anonymous
    • one year ago
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    im going to ask @dan815 and @nincompoop @Preetha to check my work

  19. anonymous
    • one year ago
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    tbh thats why i hate math cuz when you learn a formula they teach you a new one and then you get recked and have problems and then people shoot up schools

  20. anonymous
    • one year ago
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    here =)

  21. anonymous
    • one year ago
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    is fine

  22. anonymous
    • one year ago
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    look at it there =)

  23. anonymous
    • one year ago
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    @uri d okay give me a sec

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