anonymous
  • anonymous
Find f(-2) if f(x)=-x^3+2x^2+x-1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
just plug in the value -2 wherever you see x
anonymous
  • anonymous
\[f(x) = -2^3 + (2*-2^2) -2 - 1\]
anonymous
  • anonymous
just a mistake -x^3

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More answers

anonymous
  • anonymous
-13 ?
anonymous
  • anonymous
f(-2)=-(-2)^3+2(-2)^2+(-2)-1 f(-2) = 2^3 + 2(-2)^2 -2 -1 f(-2) = 8 + 16 - 3 f(-2) = 24 - 3 f(-2) = ? subract 3 from 24 t get your answer
anonymous
  • anonymous
let me know if something doesnt make sense
anonymous
  • anonymous
13 was the correct answer
anonymous
  • anonymous
yup 13
anonymous
  • anonymous
true or false f(x)=3/x+7x^2 is a polynomial
anonymous
  • anonymous
what do you think?
anonymous
  • anonymous
true
anonymous
  • anonymous
why?
anonymous
  • anonymous
i dont know
anonymous
  • anonymous
do you know what polynomial means?
anonymous
  • anonymous
yes an expression of more than two algebraic terms
anonymous
  • anonymous
yes an expression of more than two algebraic terms
anonymous
  • anonymous
polynomial means many terms "poly" meaning "many", "nomial" means term. Those terms can consist of, constant or variables or exponents but in this equation there is a problem look down in this picture that I attached
anonymous
  • anonymous
ok then it is false
anonymous
  • anonymous
can you give the reasoning?
anonymous
  • anonymous
yes becasue the dividing in the problem
anonymous
  • anonymous
correct 3/x cannot be considered as a term so it's no longer 'poly'nomial
anonymous
  • anonymous
State the degree:rst+r^2s^2+r^3s^2 can you help me with this
anonymous
  • anonymous
degree in this simply means the largest exponent of a particular variable \[r^2 + s^2 + r^3s^2\]
anonymous
  • anonymous
ok its 5
anonymous
  • anonymous
@what!? sorry I did notice the -x^3 later, after I posted, didn't feel like re-writing it.
anonymous
  • anonymous
no you have to state for each variable separately
anonymous
  • anonymous
is rst considered part of the equation in this?
anonymous
  • anonymous
yes
anonymous
  • anonymous
alright. state the variables first then.

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