Find f(-2) if f(x)=-x^3+2x^2+x-1

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Find f(-2) if f(x)=-x^3+2x^2+x-1

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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just plug in the value -2 wherever you see x
\[f(x) = -2^3 + (2*-2^2) -2 - 1\]
just a mistake -x^3

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Other answers:

-13 ?
f(-2)=-(-2)^3+2(-2)^2+(-2)-1 f(-2) = 2^3 + 2(-2)^2 -2 -1 f(-2) = 8 + 16 - 3 f(-2) = 24 - 3 f(-2) = ? subract 3 from 24 t get your answer
let me know if something doesnt make sense
13 was the correct answer
yup 13
true or false f(x)=3/x+7x^2 is a polynomial
what do you think?
true
why?
i dont know
do you know what polynomial means?
yes an expression of more than two algebraic terms
yes an expression of more than two algebraic terms
polynomial means many terms "poly" meaning "many", "nomial" means term. Those terms can consist of, constant or variables or exponents but in this equation there is a problem look down in this picture that I attached
ok then it is false
can you give the reasoning?
yes becasue the dividing in the problem
correct 3/x cannot be considered as a term so it's no longer 'poly'nomial
State the degree:rst+r^2s^2+r^3s^2 can you help me with this
degree in this simply means the largest exponent of a particular variable \[r^2 + s^2 + r^3s^2\]
ok its 5
@what!? sorry I did notice the -x^3 later, after I posted, didn't feel like re-writing it.
no you have to state for each variable separately
is rst considered part of the equation in this?
yes
alright. state the variables first then.

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