## anonymous one year ago What is the oblique asymptote of the function f(x) = the quantity x squared plus 5x plus 6 over the quantity x minus 4 ? y = x + 9 y = x - 9 y = x + 1 y = x - 1

1. anonymous

$f(x) = \frac{ x^2 + 5x + 6 }{ x -4 }$

2. anonymous

@ParthKohli @texaschic101 @sleepyjess @rational

3. anonymous

4. anonymous

do you know polynomial long division?

5. anonymous

no like i was absent for a week because i was sick now thisis my make up work and school is almost over i need to learn this to pass the exam

6. anonymous

Ok it's basically just dividing number like 10/5 but instead of numbers you are dividing expressions with expressions

7. anonymous

8. anonymous

the answer is x + 9

9. anonymous

because first you have to look at the numerator by segments

10. anonymous

k nd btw thnx do you mind if you explain how to do it so if i run across something similar to this on my exam

11. anonymous

no problem sure okay so look at the numanator look at the x^2 + 5x, you have to multiply the x-4 by something that will give you at least close to x^2 + 5x if not exactly that expression this is more like saying if you divide 10 by 3 the closest you can bring to 10 is 9 which 3*3

12. anonymous

so if you multiply x with (x-4) you will get x^2 + 4x that is at least a bit close to x^2 + 5x

13. anonymous

oh ok so like if we had 5/4 the closest would be like 4/4 or 6/4

14. anonymous

yeah exactly

15. anonymous

okay thnx i have more do you mind helping me with ill gve medals

16. anonymous

I have no problem (as long as I know how to solve it lol)

17. anonymous

thnx

18. anonymous

np