anonymous
  • anonymous
What is the oblique asymptote of the function f(x) = the quantity x squared plus 5x plus 6 over the quantity x minus 4 ? y = x + 9 y = x - 9 y = x + 1 y = x - 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[f(x) = \frac{ x^2 + 5x + 6 }{ x -4 }\]
anonymous
  • anonymous
@ParthKohli @texaschic101 @sleepyjess @rational
anonymous
  • anonymous
please help

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anonymous
  • anonymous
do you know polynomial long division?
anonymous
  • anonymous
no like i was absent for a week because i was sick now thisis my make up work and school is almost over i need to learn this to pass the exam
anonymous
  • anonymous
Ok it's basically just dividing number like 10/5 but instead of numbers you are dividing expressions with expressions
anonymous
  • anonymous
anonymous
  • anonymous
the answer is x + 9
anonymous
  • anonymous
because first you have to look at the numerator by segments
anonymous
  • anonymous
k nd btw thnx do you mind if you explain how to do it so if i run across something similar to this on my exam
anonymous
  • anonymous
no problem sure okay so look at the numanator look at the x^2 + 5x, you have to multiply the x-4 by something that will give you at least close to x^2 + 5x if not exactly that expression this is more like saying if you divide 10 by 3 the closest you can bring to 10 is 9 which 3*3
anonymous
  • anonymous
so if you multiply x with (x-4) you will get x^2 + 4x that is at least a bit close to x^2 + 5x
anonymous
  • anonymous
oh ok so like if we had 5/4 the closest would be like 4/4 or 6/4
anonymous
  • anonymous
yeah exactly
anonymous
  • anonymous
okay thnx i have more do you mind helping me with ill gve medals
anonymous
  • anonymous
I have no problem (as long as I know how to solve it lol)
anonymous
  • anonymous
thnx
anonymous
  • anonymous
np

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