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No because a right triangle has 90 degrees in it but since none of them have the measurement ABC is not a right triangle
how do you post pictures
no its not
And what would AC have to be to make it a right triangle?
1 thing ...
To solve an SSS triangle: use The Law of Cosines first to calculate one of the angles. then use The Law of Cosines again to find another angle. and finally use angles of a triangle add to 180° to find the last angle.
soh cah toa ...
agree to @jakashaka123
i remember it as some old hippie caught another hippie tripping on acid ...
Pythagorean Theorem is the lesson this derives from? I don't even know The Law of Cosines..?
sin = opposite over hypotenuse tan = opposite over adjacent cos = adjacent over hypotenuse
you would use cosine =)
I don't use that in my Geometry class? In fact I've never even been introduced to that.
you have no other angles to go off of =)
so therefor you have no other possible way of knowing =)
Except for the Pythagorean Theorem. \[a^2+b^2=c^2\]
yeah you wouldnt use that here =)
If a^2+b^2=c^2, its a right triangle.
you have no angles =)
If they are less than it's acute. Greater than it's obtuse.
and you wouldnt use cosine btw
wait yeh you would lol
3^2+5^2 does not equal 2 radical 17
So what does C have to be to make them equal?
you answered your own question for the 1st part of thiss question =)
"What would C have to be to make it a right triangle?" Was my question.
So it would be radical 34?
if a^2 +b^2 = C^2
then yeah you would need the radical other than that it would be 5.83095189485^2
you will eventually learn soh cah toa =)
you can find angle measurements with that
thats what i thought you were doing lol =)