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anonymous

  • one year ago

Parallelogram JKLM has the coordinates J (6, 7), K (12, 7), L (8, 2), and M (2, 2). Which of the following sets of points represents a dilation from the origin of parallelogram JKLM? A. J' (6, 21), K' (36, 7), L' (24, 2), M' (2, 6) B. J' (18, 21), K' (36, 21), L' (24, 6), M' (6, 6) C. J' (18, 7), K' (36, 7), L' (24, 2), M' (6, 2) D. J' (9, 10), K' (15, 10), L' (11, 5), M' (5, 5)

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  1. anonymous
    • one year ago
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    @mathmate @MrNood

  2. anonymous
    • one year ago
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    Start with choice A. Compare the coordinates of each new point with the original point. Make sure the same was done to both coordinates of all points

  3. anonymous
    • one year ago
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    Then follow onto choice B, whatever works; is your answer. (:

  4. anonymous
    • one year ago
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    ill try. thanks :)

  5. MrNood
    • one year ago
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    we discussed this before If it is a dilation about the origin then all values will be multiplied by the |SAME factor you can see in the first one J(6,7) => J' (6,21) does NOT meet that at x is multiplied by 1 but y is multiplied by 3 have a look at all the answers and find one where the transform has a common factor for all points...

  6. anonymous
    • one year ago
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    i got b

  7. anonymous
    • one year ago
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    i multiplied everything by 3 and it turned out to be b.

  8. anonymous
    • one year ago
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    @rileychampion365

  9. MrNood
    • one year ago
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    as before - if you understand the concept and are confident of your answer - go with it

  10. anonymous
    • one year ago
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    i got it right again! :)

  11. MrNood
    • one year ago
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    well done - that's a habit worth acquiring :-)

  12. anonymous
    • one year ago
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    do i still do the same if the corrdinates are negative?

  13. MrNood
    • one year ago
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    yes (remember to keep the negative sign after you multiply

  14. anonymous
    • one year ago
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    alright thanks!

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