Parallelogram JKLM has the coordinates J (6, 7), K (12, 7), L (8, 2), and M (2, 2). Which of the following sets of points represents a dilation from the origin of parallelogram JKLM? A. J' (6, 21), K' (36, 7), L' (24, 2), M' (2, 6) B. J' (18, 21), K' (36, 21), L' (24, 6), M' (6, 6) C. J' (18, 7), K' (36, 7), L' (24, 2), M' (6, 2) D. J' (9, 10), K' (15, 10), L' (11, 5), M' (5, 5)

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Parallelogram JKLM has the coordinates J (6, 7), K (12, 7), L (8, 2), and M (2, 2). Which of the following sets of points represents a dilation from the origin of parallelogram JKLM? A. J' (6, 21), K' (36, 7), L' (24, 2), M' (2, 6) B. J' (18, 21), K' (36, 21), L' (24, 6), M' (6, 6) C. J' (18, 7), K' (36, 7), L' (24, 2), M' (6, 2) D. J' (9, 10), K' (15, 10), L' (11, 5), M' (5, 5)

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Start with choice A. Compare the coordinates of each new point with the original point. Make sure the same was done to both coordinates of all points
Then follow onto choice B, whatever works; is your answer. (:

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ill try. thanks :)
we discussed this before If it is a dilation about the origin then all values will be multiplied by the |SAME factor you can see in the first one J(6,7) => J' (6,21) does NOT meet that at x is multiplied by 1 but y is multiplied by 3 have a look at all the answers and find one where the transform has a common factor for all points...
i got b
i multiplied everything by 3 and it turned out to be b.
as before - if you understand the concept and are confident of your answer - go with it
i got it right again! :)
well done - that's a habit worth acquiring :-)
do i still do the same if the corrdinates are negative?
yes (remember to keep the negative sign after you multiply
alright thanks!

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