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anonymous
 one year ago
Please help I will medal!
I am confused on how to solve this question:
A thundercloud has an electric charge of 43.2 C near the top of the cloud and 38.7 near the bottom of the cloud. The magnitude of the electric force between these two charges is 3.95 x 10^6 N. What is the average separation between these charges? (kc=8.99 x 10^9 N m^2/C^2)
anonymous
 one year ago
Please help I will medal! I am confused on how to solve this question: A thundercloud has an electric charge of 43.2 C near the top of the cloud and 38.7 near the bottom of the cloud. The magnitude of the electric force between these two charges is 3.95 x 10^6 N. What is the average separation between these charges? (kc=8.99 x 10^9 N m^2/C^2)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@iGreen @gleem @emma.monsterr

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im sorry, i didnt learn these yet but good luck :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@OpenStudyRocks5* @Greg_D @horsegirl325

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The only thing I can think of is to subtract maybe but that comes out too 81.5 and I dont think thats right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hi! You can use the Coulomb's force law here...

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0seems they want you to use coulumbs law F = k q1 q2 / r^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I believe the equation I am supposed to use is in the question above. However, I dont understand how to solve with this equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0note that you are given both charges: \[q_1=43.2C\] \[q_2=38.7C\] and \[F=3.95\times 10^6 N\] you are also given kc, which is k in the eq of IrishBoy you can just replace and finde the value for r, which represents the distance.... give it a try!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I would solve 3.95 x 10^6 N =8.99 x 10^9 N m^2/C^2 (43.2C)(38.7C) / r^2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah!! get r from there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok can you help me solve it? Just so I know I dont get the wrong answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we can both make calculations and check togheter... let me see what i get...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright I'll let you know what I get.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just a detail, we dont need to use the minus sign for the second charge!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 1.95 x 10^3 what did you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the same!!! :) what do you thinks the units should be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sure! it is a distence, so meters!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This correct right? @glittergurl0101

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, this is correct :) @Ella31224
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