Please help I will medal! I am confused on how to solve this question: A thundercloud has an electric charge of 43.2 C near the top of the cloud and -38.7 near the bottom of the cloud. The magnitude of the electric force between these two charges is 3.95 x 10^6 N. What is the average separation between these charges? (kc=8.99 x 10^9 N m^2/C^2)

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Please help I will medal! I am confused on how to solve this question: A thundercloud has an electric charge of 43.2 C near the top of the cloud and -38.7 near the bottom of the cloud. The magnitude of the electric force between these two charges is 3.95 x 10^6 N. What is the average separation between these charges? (kc=8.99 x 10^9 N m^2/C^2)

Physics
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Im sorry, i didnt learn these yet but good luck :/
ok thank you :/

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The only thing I can think of is to subtract maybe but that comes out too 81.5 and I dont think thats right
Hi! You can use the Coulomb's force law here...
seems they want you to use coulumbs law F = k q1 q2 / r^2
I believe the equation I am supposed to use is in the question above. However, I dont understand how to solve with this equation.
note that you are given both charges: \[q_1=43.2C\] \[q_2=-38.7C\] and \[F=3.95\times 10^6 N\] you are also given kc, which is k in the eq of IrishBoy you can just replace and finde the value for r, which represents the distance.... give it a try!
So I would solve 3.95 x 10^6 N =8.99 x 10^9 N m^2/C^2 (43.2C)(-38.7C) / r^2?
yeah!! get r from there
Ok can you help me solve it? Just so I know I dont get the wrong answer?
we can both make calculations and check togheter... let me see what i get...
Alright I'll let you know what I get.
just a detail, we dont need to use the minus sign for the second charge!
Alright!
I got 1.95 x 10^3 what did you get?
the same!!! :) what do you thinks the units should be?
m?
sure! it is a distence, so meters!
good work :)
Thank you!
This correct right? @glittergurl0101
Yes, this is correct :) @Ella31224

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