anonymous
  • anonymous
Please help I will medal! I am confused on how to solve this question: A thundercloud has an electric charge of 43.2 C near the top of the cloud and -38.7 near the bottom of the cloud. The magnitude of the electric force between these two charges is 3.95 x 10^6 N. What is the average separation between these charges? (kc=8.99 x 10^9 N m^2/C^2)
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@iGreen @gleem @emma.monsterr
anonymous
  • anonymous
Im sorry, i didnt learn these yet but good luck :/
anonymous
  • anonymous
ok thank you :/

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
@OpenStudyRocks5* @Greg_D @horsegirl325
anonymous
  • anonymous
The only thing I can think of is to subtract maybe but that comes out too 81.5 and I dont think thats right
anonymous
  • anonymous
Hi! You can use the Coulomb's force law here...
IrishBoy123
  • IrishBoy123
seems they want you to use coulumbs law F = k q1 q2 / r^2
anonymous
  • anonymous
I believe the equation I am supposed to use is in the question above. However, I dont understand how to solve with this equation.
anonymous
  • anonymous
@Greg_D
anonymous
  • anonymous
note that you are given both charges: \[q_1=43.2C\] \[q_2=-38.7C\] and \[F=3.95\times 10^6 N\] you are also given kc, which is k in the eq of IrishBoy you can just replace and finde the value for r, which represents the distance.... give it a try!
anonymous
  • anonymous
So I would solve 3.95 x 10^6 N =8.99 x 10^9 N m^2/C^2 (43.2C)(-38.7C) / r^2?
anonymous
  • anonymous
yeah!! get r from there
anonymous
  • anonymous
Ok can you help me solve it? Just so I know I dont get the wrong answer?
anonymous
  • anonymous
we can both make calculations and check togheter... let me see what i get...
anonymous
  • anonymous
Alright I'll let you know what I get.
anonymous
  • anonymous
just a detail, we dont need to use the minus sign for the second charge!
anonymous
  • anonymous
Alright!
anonymous
  • anonymous
I got 1.95 x 10^3 what did you get?
anonymous
  • anonymous
the same!!! :) what do you thinks the units should be?
anonymous
  • anonymous
m?
anonymous
  • anonymous
sure! it is a distence, so meters!
anonymous
  • anonymous
good work :)
anonymous
  • anonymous
Thank you!
anonymous
  • anonymous
This correct right? @glittergurl0101
anonymous
  • anonymous
Yes, this is correct :) @Ella31224

Looking for something else?

Not the answer you are looking for? Search for more explanations.