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souvik
 one year ago
integration
souvik
 one year ago
integration

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souvik
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}\sqrt{\tan x} ~~dx\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Make a substitution \[t^2 = tanx\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x = \tan^{1} t^2\] can you do the rest?

souvik
 one year ago
Best ResponseYou've already chosen the best response.0i found\[\int\limits_{}^{}\frac{ 2t^2 }{ 1+t^4 }dt\] now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits \frac{ 2t^2 }{ 1+t^4 }dt \implies \int\limits \frac{ t^2+1+t^21 }{ t^4+1 } dt = \int\limits \frac{ t^2+1 }{ t^4+1 }dt + \int\limits \frac{ t^21 }{ t^4+1 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you'll have to do the integrals separately now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits \frac{ t^2+1 }{ t^2+1 } dt \implies \int\limits \frac{ 1+1/t^2 }{ t^2+1/t^2 } dt\] now do another u substation do so similarly with other integral.

souvik
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}\frac{ 11/t^2 }{t^2+1/t^2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let u = t1/t^2 for the first integral and similarly you would let u = t+1/t for the second integral (the one you presented)
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