Can someone check my answer? Algebra II

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Can someone check my answer? Algebra II

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[2x+5/x^2-3x-10 \left( + \right) x+1/x+2\]
I got the answer ...\[x(x-2)/(x-5)(x+2)\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

  • phi
is this \[ \frac{2x+5}{x^2-3x-10} + \frac{ x+1}{x+2} \]?
yes @phi
  • phi
first factor the bottom of the first fraction (to get a better idea of what is going on) \[ \frac{2x+5}{x^2-3x-10} + \frac{ x+1}{x+2} \\ \frac{2x+5}{(x+2)(x-5)} + \frac{ x+1}{x+2} \]
That is what I did
  • phi
to get a common denominator, multiply the second fraction by (x-5) (top and bottom) \[ \frac{2x+5}{(x+2)(x-5)} + \frac{ (x+1)}{(x+2)} \frac{(x-5)}{(x-5)} \] now we can add the tops. First, multiply out the top of the second fraction: \[ \frac{2x+5}{(x+2)(x-5)} + \frac{ x^2-4x-5} {(x+2)(x-5)}\]
  • phi
now add the tops and put the sum over the common denominator \[\frac{ x^2-2x} {(x+2)(x-5)}\] it looks like we can factor out an x \[ \frac{ x(x-2)} {(x+2)(x-5)}\] yes, it looks like the same thing as what you posted.
awesome! thanks for helping me out so quickly! @phi

Not the answer you are looking for?

Search for more explanations.

Ask your own question