anonymous one year ago Can someone check my answer? Algebra II

1. anonymous

$2x+5/x^2-3x-10 \left( + \right) x+1/x+2$

2. anonymous

I got the answer ...$x(x-2)/(x-5)(x+2)$

3. anonymous

@Hero

4. anonymous

@Michele_Laino @nincompoop

5. anonymous

@phi

6. anonymous

@texaschic101

7. phi

is this $\frac{2x+5}{x^2-3x-10} + \frac{ x+1}{x+2}$?

8. anonymous

yes @phi

9. phi

first factor the bottom of the first fraction (to get a better idea of what is going on) $\frac{2x+5}{x^2-3x-10} + \frac{ x+1}{x+2} \\ \frac{2x+5}{(x+2)(x-5)} + \frac{ x+1}{x+2}$

10. anonymous

That is what I did

11. phi

to get a common denominator, multiply the second fraction by (x-5) (top and bottom) $\frac{2x+5}{(x+2)(x-5)} + \frac{ (x+1)}{(x+2)} \frac{(x-5)}{(x-5)}$ now we can add the tops. First, multiply out the top of the second fraction: $\frac{2x+5}{(x+2)(x-5)} + \frac{ x^2-4x-5} {(x+2)(x-5)}$

12. phi

now add the tops and put the sum over the common denominator $\frac{ x^2-2x} {(x+2)(x-5)}$ it looks like we can factor out an x $\frac{ x(x-2)} {(x+2)(x-5)}$ yes, it looks like the same thing as what you posted.

13. anonymous

awesome! thanks for helping me out so quickly! @phi