anonymous
  • anonymous
If the efficiency of a heat engine that does 1.00 × 10^3 J of work is 70 percent, then what is the heat input? A. 1.43 × 10 J B. -7.00 × 10^2 J C. 9.30 × 10^2 J D. 1.43 × 10^3 J **Not sure! thanks!!:)
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Michele_Laino
  • Michele_Laino
by definition, the efficiency is given by the subsequent formula: \[\eta = \frac{L}{Q}\]
anonymous
  • anonymous
okay! so 70/1.00*10^3 ?
Michele_Laino
  • Michele_Laino
no, it is: \[Q = \frac{L}{\eta } = \frac{{{{10}^3}}}{{0.7}}\]

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Michele_Laino
  • Michele_Laino
\[\Large Q = \frac{L}{\eta } = \frac{{{{10}^3}}}{{0.7}}\]
anonymous
  • anonymous
ohh oops!! okay so then we get 1428.57 ? so is that choice D?
Michele_Laino
  • Michele_Laino
yes! that's right!
anonymous
  • anonymous
yay!! thank you:)
Michele_Laino
  • Michele_Laino
thanks!! :)

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