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anonymous

  • one year ago

By using the following reactions, calculate the heat of formation of pentane (C5H12) gas from carbon and hydrogen gas. C (s) + O2 (g) CO2 (g), H = 395 kJ/mol H2 (g) + 1/2O2 (g) H2O (l), H = 285 kJ/mol C5H12 (g) + 8O2 5CO2 (g) + 6H2O (l), H = 3.54 × 103 kJ/mol

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  1. anonymous
    • one year ago
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    My teacher told me yesterday in tutoring that I need to reverse some of them and multiply others and I'm just really lost with this.

  2. amurciano2
    • one year ago
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    I know how to do this Give me 5min.

  3. amurciano2
    • one year ago
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    Can you post a pic of the question? There we no arrows.

  4. anonymous
    • one year ago
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    My bad, are you still available?

  5. anonymous
    • one year ago
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    C (s) + O2 (g) -> CO2 (g), H = 395 kJ/mol

  6. anonymous
    • one year ago
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    H2 (g) + 1/2O2 (g) -> H2O (l), H = 285 kJ/mol

  7. anonymous
    • one year ago
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    C5H12 (g) + 8O2 -> 5CO2 (g) + 6H2O (l), H = 3.54 × 103 kJ/mol

  8. amurciano2
    • one year ago
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    Yup I can still help.

  9. anonymous
    • one year ago
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    I added the arrows

  10. anonymous
    • one year ago
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    does that work?

  11. amurciano2
    • one year ago
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    I think you are missing a reaction,but I'm not positive

  12. amurciano2
    • one year ago
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    What is the equation you are trying to get, I assume it is this one

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  13. anonymous
    • one year ago
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    I am simply trying to find the heat of formation of those three equations

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spraguer (Moderator)
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