By using the following reactions, calculate the heat of formation of pentane (C5H12) gas from carbon and hydrogen gas. C (s) + O2 (g) CO2 (g), H = 395 kJ/mol H2 (g) + 1/2O2 (g) H2O (l), H = 285 kJ/mol C5H12 (g) + 8O2 5CO2 (g) + 6H2O (l), H = 3.54 × 103 kJ/mol

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By using the following reactions, calculate the heat of formation of pentane (C5H12) gas from carbon and hydrogen gas. C (s) + O2 (g) CO2 (g), H = 395 kJ/mol H2 (g) + 1/2O2 (g) H2O (l), H = 285 kJ/mol C5H12 (g) + 8O2 5CO2 (g) + 6H2O (l), H = 3.54 × 103 kJ/mol

Chemistry
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My teacher told me yesterday in tutoring that I need to reverse some of them and multiply others and I'm just really lost with this.
I know how to do this Give me 5min.
Can you post a pic of the question? There we no arrows.

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My bad, are you still available?
C (s) + O2 (g) -> CO2 (g), H = 395 kJ/mol
H2 (g) + 1/2O2 (g) -> H2O (l), H = 285 kJ/mol
C5H12 (g) + 8O2 -> 5CO2 (g) + 6H2O (l), H = 3.54 × 103 kJ/mol
Yup I can still help.
I added the arrows
does that work?
I think you are missing a reaction,but I'm not positive
What is the equation you are trying to get, I assume it is this one
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I am simply trying to find the heat of formation of those three equations

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